Auto scrolling to a cell with a specific value

Question

I have a list of numbers in a table view like this.

As you can see th

Answer 1

Swift 3.0

 let indexPath = NSIndexPath(forRow: 5, inSection: 0)
 tableView.scrollToRow(at: indexPath, at: .top, animated: true)

Swift 4.0

let lastRowIndex = self.tblRequestStatus!.numberOfRows(inSection: 0) - 1
let pathToLastRow = IndexPath.init(row: lastRowIndex, section: 0)
tableView.scrollToRow(at: pathToLastRow, at: .none, animated: false)

Answer 2

Do this to find the first element in the array that is equal to groupNoToScroll. Then, go to that row.

    var rowToGoTo:Int = 0 //Rather use the Swift find function.
    for x in items{
        if x == groupNoToScroll{
            break
        }
        rowToGoTo++
    }

    let lastRow = tableView.indexPathsForVisibleRows()?.last as NSIndexPath
    if indexPath.row == lastRow.row {
        if scrollToTime == true {
           let indexPath = NSIndexPath(row: rowToGoTo, section: 0)
           tblBusList.scrollToRow(at: indexPath as IndexPath, at: .top, animated: true)
        }
    }

But I would recommend doing this in viewDidAppear.

As Isuru pointed out rather use the find function.

Answer 3

Swift 4:

let indexPath = IndexPath(row: row, section: section)
tableView.scrollToRow(at: indexPath, at: .top, animated: true)

(first, of course, you have to assign values to row and section based on which cell you want to scroll to)

Answer 4

You can use find the index of the item(which will be its row), and then scroll to that index.
find function returns the index of a particular element in the array.

if let index = find(items, groupNoToScroll)
{
    let indexPath = NSIndexPath(forRow: index, inSection: 0)
    tableView.scrollToRowAtIndexPath(indexPath, atScrollPosition: .Top, animated: true)
}