How to get current hour (time of day) in linux kernel space

Question

I\'m writing a kernel module that checks to see if the time is between two specified hours, and disables input if it is. This has to do with me wanting to make sure I go to

Answer 1

We can use clock_gettime function with CLOCK_REALTIME as the type of clock.

Reference http://linux.die.net/man/3/clock_gettime

Just doing a strace on date executable gives us an idea to get the current date in the kernel mode.

Answer 2

time_to_tm function can be of your help, which returns the structure tm. Timezone available in variable sys_tz, it can help you to set your offset properly to get local time.

Answer 3

This works well for me:

#include <linux/time.h>
...
/* getnstimeofday - Returns the time of day in a timespec */
void getnstimeofday(struct timespec *ts)

For getting usual time format you can use:

printk("TIME: %.2lu:%.2lu:%.2lu:%.6lu \r\n",
                   (curr_tm.tv_sec / 3600) % (24),
                   (curr_tm.tv_sec / 60) % (60),
                   curr_tm.tv_sec % 60,
                   curr_tm.tv_nsec / 1000);

Answer 4

Converting the do_gettimeofday result to an hour is pretty simple, since it starts at midnight GMT.

time_t t = time(0);
time_t SecondsOfDay = t % (24*60*60);
time_t HourGMT = SecondsOfDay / (60*60);

Then adjust for your local timezone

Answer 5

To get the local time in kernel, add the below code snippet your kernel driver:

struct timeval time;
unsigned long local_time;

do_gettimeofday(&time);
local_time = (u32)(time.tv_sec - (sys_tz.tz_minuteswest * 60));
rtc_time_to_tm(local_time, &tm);

printk(" @ (%04d-%02d-%02d %02d:%02d:%02d)\n", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);