so i have a bunch of simple documents like
{
\"foos\": [
ObjectId(\"5105862f2b5e30877c685c58\"),
ObjectId(\"5105862f2b5e30877c685c57\"),
Obje
Include the $group operator pipeline stage after the $project step as follows:
db.profil.aggregate([
{ "$match":{ "typ": "Organisation" } },
{ "$project": {
"fooos": { "$size": "$foos" }
} },
{ "$group": {
"_id": null,
"count": {
"$sum": "$fooos"
}
} }
])
This will group all the input documents from the previous $project stage and applies the accumulator expression $sum on the fooos
field within the group to get the total (using your last example):
This can also be done by-passing the $project pipeline as:
db.profil.aggregate([
{ "$match": { "typ": "Organisation" } },
{ "$group": {
"_id": null,
"count": {
"$sum": { "$size": "$foos" }
}
} }
])
Output
/* 0 */
{
"result" : [
{
"_id" : null,
"count" : 24
}
],
"ok" : 1
}
I know this is an old question but you can bypass project altogether if you want, so how about this?
db.profil.aggregate([
{
"$match":{ "typ": "Organisation" }
},
{
"$group":
{
"_id": null,
"count":
{
"$sum": { "$size": "$foos" }
}
}
}])
The output remains the same and it seems it's (slightly) faster.