I\'m trying to recreate the Underscore pluck function using pure JS. However, I keep getting an array of undefineds being returned, instead of the actual values from the pr
var array = {
name: ["Pedro", "João", "Francisco", "Diogo"],
ID: [1,2,3,4]
};
console.log(pluck(array,'name'));
function pluck(array, key) {
return (array[key]);
};
JSFiddle
You can use this function, click in JSFiddle to see a Example!! :)
Here's a working solution
function pluck(array,key){
var a = [],
i1 = -1, i2 = array.length,
o ;
while(++i1 < i2)
{
o = array[i1] ; // you have to use the bracket operator here
if(o.hasOwnProperty(key)) a[a.length] = o[key] ;
}
return a ;
}
I didn't really change all that much. The reason why your code failed is because you used the dot operator .key
to access the named property of the array elements instead of the bracket operator [key]
. When using a reference as a key you need to use the bracket operator.
You can do it with the native JavaScript .map()
:
Array.prototype.pluck = function(key) {
return this.map(function(object) { return object[key]; });
};
edit — modifying built-in prototype objects should be done with care; a better way to add the function (should you be OK with the idea of doing so in general) would be with Object.defineProperty
so that it can be made non-enumerable:
Object.defineProperty(Array.prototype, "pluck", {
value: function(key) {
return this.map(function(object) { return object[key]; });
}
});
In ES5:
function pluck(array, key) {
return array.map(function(obj) {
return obj[key];
});
}
In ES6:
function pluck(array, key) {
return array.map(o => o[key]);
}
You are so close. You need to change:
newArr.push(arr[i].key);
to:
newArr.push(arr[i][key]);
Consider this:
var obj = { myKey: 'my Value', theKey: 'another value' };
var theKey = 'myKey';
alert(obj.theKey); // another value
alert(obj[theKey]); // my Value
// You can also send in strings here:
alert(obj['theKey']); // another value
Hope you get my point.
How about a reduce:
$.pluck = function(arr, key) {
return arr.reduce(function(p, v) {
return p.concat(v[key]);
}, []);
}
var people = [
{ name: 'James', age: 26 },
{ name: 'Fred', age: 56 }
];
$.pluck(people, 'age');
=> [26, 56]
$.pluck(people, 'name');
=> ['James', 'Fred']