Java: convert int to InetAddress

Question

I have an int which contains an IP address in network byte order, which I would like to convert to an InetAddress object. I see that there is an <

Answer 1

If you're using Google's Guava libraries, InetAddresses.fromInteger does exactly what you want. Api docs are here

If you'd rather write your own conversion function, you can do something like what @aalmeida suggests, except be sure to put the bytes in the right order (most significant byte first).

Answer 2

This should work:

int ipAddress = ....
byte[] bytes = BigInteger.valueOf(ipAddress).toByteArray();
InetAddress address = InetAddress.getByAddress(bytes);

You might have to swap the order of the byte array, I can't figure out if the array will be generated in the correct order.

Answer 3

This may work try

public static String intToIp(int i) {
        return ((i >> 24 ) & 0xFF) + "." +
               ((i >> 16 ) & 0xFF) + "." +
               ((i >>  8 ) & 0xFF) + "." +
               ( i        & 0xFF);
    }

Answer 4

public static byte[] int32toBytes(int hex) {
    byte[] b = new byte[4];
    b[0] = (byte) ((hex & 0xFF000000) >> 24);
    b[1] = (byte) ((hex & 0x00FF0000) >> 16);
    b[2] = (byte) ((hex & 0x0000FF00) >> 8);
    b[3] = (byte) (hex & 0x000000FF);
    return b;

}

you can use this function to turn int to bytes;