Slicing a dictionary by keys that start with a certain string

Question

This is pretty simple but I\'d love a pretty, pythonic way of doing it. Basically, given a dictionary, return the subdictionary that contains only those keys that start with

Answer 1

In functional style:

dict(filter(lambda item: item[0].startswith(string),sourcedict.iteritems()))

Answer 2

How about this:

in python 2.x :

def slicedict(d, s):
    return {k:v for k,v in d.iteritems() if k.startswith(s)}

In python 3.x :

def slicedict(d, s):
    return {k:v for k,v in d.items() if k.startswith(s)}

Answer 3

In Python 3 use items() instead:

def slicedict(d, s):
    return {k:v for k,v in d.items() if k.startswith(s)}