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Selenium Finding elements by class name in python

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清酒与你
清酒与你 2020-12-14 06:05

How can I filter elements which having a same class?


 
  
Link1.



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  • 死守一世寂寞
    2020-12-14 06:13

    As per the HTML:

    <html>
    <body>
    <p class="content">Link1.</p>
    </body>
<html>
<html>
    <body>
    <p class="content">Link2.</p>
    </body>
<html>

    Two(2) <p> elements are having the same class content.

    So to filter the elements having the same class i.e. content and create a list you can use either of the following Locator Strategies:

    • Using class_name:

      elements = driver.find_elements_by_class_name("content")

    • Using css_selector:

       elements = driver.find_elements_by_css_selector(".content")

    • Using xpath:

      elements = driver.find_elements_by_xpath("//*[@class='content']")

    Ideally, to click on the element you need to induce WebDriverWait for the visibility_of_all_elements_located() and you can use either of the following Locator Strategies:

    • Using CLASS_NAME:

      elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CLASS_NAME, "content")))

    • Using CSS_SELECTOR:

      elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, ".content")))

    • Using XPATH:

      elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//*[@class='content']")))

    • Note : You have to add the following imports :

      from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

    References

    You can find a couple of relevant discussions in:

    • How to identify an element through classname even though there are multiple elements with the same classnames using Selenium and Python
    • Unable to locate element using className in Selenium and Java
    • What are properties of find_element_by_class_name in selenium python?
    • How to locate the last web element using classname attribute through Selenium and Python
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  • 醉话见心
    2020-12-14 06:28

    The most simple way is to use find_element_by_class_name('class_name')

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  • 爱一瞬间的悲伤
    2020-12-14 06:28

    Use nth-child, for example: http://www.w3schools.com/cssref/sel_nth-child.asp

    driver.find_element(By.CSS_SELECTOR, 'p.content:nth-child(1)')

    or http://www.w3schools.com/cssref/sel_firstchild.asp

    driver.find_element(By.CSS_SELECTOR, 'p.content:first-child')
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  • 别跟我提以往
    2020-12-14 06:36

    You can try to get the list of all elements with class = "content" by using find_elements_by_class_name:

    a = driver.find_elements_by_class_name("content")

    Then you can click on the link that you are looking for.

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  • 情深已故
    2020-12-14 06:37

    By.CLASS_NAME was not yet mentioned:

    from selenium.webdriver.common.by import By

driver.find_element(By.CLASS_NAME, "content")

    This is the list of attributes which can be used as locators in By:

    CLASS_NAME
    CSS_SELECTOR
    ID
    LINK_TEXT
    NAME
    PARTIAL_LINK_TEXT
    TAG_NAME
    XPATH

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