Before you show me duplicates, please note that I\'ve searched through the site an have found some examples but not quite specific to my prob
Table User: UserId
Table Friendship: FriendshipId
Table UserFriendships: UserId, FriendshipId, FriendshipStatus
You can add a UNIQUE constraint to prevent a User from being in a Friendship twice.
You have Users and Friendships. Users can join Friendships (which can be 0 or more Users) by creating a record in the third table.
Making the primary key for the FRIENDSHIP
table to be:
...will ensure that you can't have duplicates in order. Meaning, it will stop you from adding duplicates of userid "123" and friendid "789". If you include the status column, that's no longer the case, because a different status value will allow for duplicates of the userid and friendid column.
In order to stop reverse pairs -- userid "789" and friendid "123" -- you need to either include the logic to check if the pair already exists in the table in a stored procedure, function, or trigger. A CHECK constraint of userid < friendid would stop a valid attempt to add userid "789" and friendid "123" if the reverse doesn't already exist.
INSERT INTO FRIENDSHIP
SELECT @userid, @friendid, 1
FROM FRIENDSHIP f
WHERE NOT EXISTS(SELECT NULL
FROM FRIENDSHIP t
WHERE (t.userid = @friendid AND t.friendid = @userid)
OR (t.userid = @userid AND t.friendid = @friendid)
Quassnoi wrote an article explaining why you might want to have a version of the table with two rows per pair, to make queries easier: http://explainextended.com/2009/03/07/selecting-friends/
(the article talks about MySQL but it is worth bearing in mind as a performance technique for any SQL database)
I did a small change to perform the internal query and returns only a record when exists (dual table) at the end finish parentheses
INSERT INTO FRIENDSHIP
SELECT @userid, @friendid, 1
FROM DUAL f
WHERE NOT EXISTS(SELECT NULL
FROM FRIENDSHIP t
WHERE (t.userid = @friendid AND t.friendid = @userid)
OR (t.userid = @userid AND t.friendid = @friendid) )
User(UserID) Friendship(User1ID, User2ID, FriendshipStatus)
Check constraint: User1ID < User2ID
Unique constraint: User1ID, User2ID