MongoDB return True if document exists

Question

I want to return true if a userID already exists and false otherwise from my collection.I have this function but it always returns True.

def alr         


        

Answer 1

This worked for me

result = num.find({"num": num}, { "_id": 0 }) 
if result.count() > 0:  
   return
else:
   num.insert({"num": num, "DateTime": DateTime })

Answer 2

I guess am very late to post the solution. Anyways i have encountered same problem today and following worked for me. Hope this help to others.

return db.mycollection.find({'UserIDS': newID}).count > 0

Answer 3

If you're using Motor, find() doesn't do any communication with the database, it merely creates and returns a MotorCursor:

http://motor.readthedocs.org/en/stable/api/motor_collection.html#motor.MotorCollection.find

Since the MotorCursor is not None, Python considers it a "true" value so your function returns True. If you want to know if at least one document exists that matches your query, try find_one():

@gen.coroutine
def alreadyExists(newID):
    doc = yield db.mycollection.find_one({'UserIDS': { "$in": newID}})
    return bool(doc)

Notice you need a "coroutine" and "yield" to do I/O with Tornado. You could also use a callback:

def alreadyExists(newID, callback):
    db.mycollection.find_one({'UserIDS': { "$in": newID}}, callback=callback)

For more on callbacks and coroutines, see the Motor tutorial:

http://motor.readthedocs.org/en/stable/tutorial.html

If you're using PyMongo and not Motor, it's simpler:

def alreadyExists(newID):
    return bool(db.mycollection.find_one({'UserIDS': { "$in": newID}}))

Final note, MongoDB's $in operator takes a list of values. Is newID a list? Perhaps you just want:

find_one({'UserIDS': newID})

Answer 4

Note: This answer is outdated. More recent versions of MongoDB can use the far more efficient method db.collection.countDocuments. See the answer by Xavier Guihot for a better solution.

find doesn't return a boolean value, it returns a cursor. To check if that cursor contains any documents, use the cursors count-method.

if db.mycollection.find({'UserIDS': { "$in": newID}}).count() > 0.

By the way: is newID an array? When it isn't, you should not use the $in-operator. You can simply do find({'UserIDS': newID})

Answer 5

Starting Mongo 4.0.3/PyMongo 3.7.0, we can use count_documents:

if db.collection.count_documents({ 'UserIDS': newID }, limit = 1) != 0:
  # do something

Used with the optional parameter limit, this provides a way to find if there is at least one matching occurrence.

Limiting the number of matching occurrences makes the collection scan stop as soon as a match is found instead of going through the whole collection.

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Note that this can also be written as follow since 1 is interpreted as True in a python condition:

if db.collection.count_documents({ 'UserIDS': newID }, limit = 1):
  # do something

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In earlier versions of Mongo/Pymongo, count could be used (deprecated and replaced by count_documents in Mongo 4):

if db.collection.count({ 'UserIDS': newID }, limit = 1) != 0:
  # do something

Answer 6

One liner solution in mongodb query

db.mycollection.find({'UserIDS': { "$in": newID}}).count() > 0 ? true : false