I\'m using .Net 3.5 (C#) and I\'ve heard the performance of C# List
is \"bad\", since it memory copies for all elements to form a new array. Is
For any kind of List/ICollection where it knows the length, it can allocate an array of exactly the right size from the start.
T[] destinationArray = new T[this._size];
Array.Copy(this._items, 0, destinationArray, 0, this._size);
return destinationArray;
If your source type is IEnumerable (not a List/Collection) then the source is:
items = new TElement[4];
..
if (no more space) {
TElement[] newItems = new TElement[checked(count * 2)];
Array.Copy(items, 0, newItems, 0, count);
items = newItems;
It starts at size 4 and grows exponentially, doubling each time it runs out of space. Each time it doubles, it has to reallocate memory and copy the data over.
If we know the source-data size, we can avoid this slight overhead. However in most cases eg array size <=1024, it will execute so quickly, that we don't even need to think about this implementation detail.
References: Enumerable.cs, List.cs (F12ing into them), Joe's answer
No that's not true. Performance is good since all it does is memory copy all elements (*) to form a new array.
Of course it depends on what you define as "good" or "bad" performance.
(*) references for reference types, values for value types.
EDIT
In response to your comment, using Reflector is a good way to check the implementation (see below). Or just think for a couple of minutes about how you would implement it, and take it on trust that Microsoft's engineers won't come up with a worse solution.
public T[] ToArray()
{
T[] destinationArray = new T[this._size];
Array.Copy(this._items, 0, destinationArray, 0, this._size);
return destinationArray;
}
Of course, "good" or "bad" performance only has a meaning relative to some alternative. If in your specific case, there is an alternative technique to achieve your goal that is measurably faster, then you can consider performance to be "bad". If there is no such alternative, then performance is "good" (or "good enough").
EDIT 2
In response to the comment: "No re-construction of objects?" :
No reconstruction for reference types. For value types the values are copied, which could loosely be described as reconstruction.
Yes, it's true that it does a memory copy of all elements. Is it a performance problem? That depends on your performance requirements.
A List
contains an array internally to hold all the elements. The array grows if the capacity is no longer sufficient for the list. Any time that happens, the list will copy all elements into a new array. That happens all the time, and for most people that is no performance problem.
E.g. a list with a default constructor starts at capacity 16, and when you .Add()
the 17th element, it creates a new array of size 32, copies the 16 old values and adds the 17th.
The size difference is also the reason why ToArray()
returns a new array instance instead of passing the private reference.
This is what Microsoft's official documentation says about List.ToArray's time complexity
The elements are copied using Array.Copy, which is an O(n) operation, where n is Count.
Then, looking at Array.Copy, we see that it is usually not cloning the data but instead using references:
If sourceArray and destinationArray are both reference-type arrays or are both arrays of type Object, a shallow copy is performed. A shallow copy of an Array is a new Array containing references to the same elements as the original Array. The elements themselves or anything referenced by the elements are not copied. In contrast, a deep copy of an Array copies the elements and everything directly or indirectly referenced by the elements.
So in conclusion, this is a pretty efficient way of getting an array from a list.
Reasons to call ToArray()
Reasons not to call ToArray()
taken from here
it creates new references in an array, but that's just the only thing that that method could and should do...