How do I convert a hex triplet to an RGB tuple and back?

Question

I\'d like to convert a hex triplet to an RGB tuple and then convert a tuple to a hex triplet.

Answer 1

Here you go. I use it to convert color to graphviz color format in #RGBA format with prefix=#.

def rgba_hex( color, prefix = '0x' ):
    if len( color ) == 3:
       color = color + (255,)
    hexColor = prefix + ''.join( [ '%02x' % x for x in color ] )
    return hexColor

USAGE:

In [3]: rgba_hex( (222, 100, 34) )
Out[3]: '0xde6422ff'

In [4]: rgba_hex( (0,255,255) )
Out[4]: '0x00ffffff'

In [5]: rgba_hex( (0,255,255,0) )
Out[5]: '0x00ffff00'

Answer 2

I found a simple way:

red, green, blue = bytes.fromhex("aabbcc")

Answer 3

with matplotlib

matplotlib uses RGB tuples with values between 0 and 1:

from matplotlib.colors import hex2color, rgb2hex

hex_color = '#00ff00'
rgb_color = hex2color(hex_color)
hex_color_again = rgb2hex(rgb_color)

both rgb_color and hex_color are in a format acceptable by matplotlib.

with webcolors

html uses RGB tuples with values between 0 and 255.

you can convert between them with the module webcolors, using the functions hex_to_rgb, rgb_to_hex

Answer 4

def hex_to_int_color(v):
    if v[0] == '#':
        v = v[1:]
    assert(len(v) == 6)
    return int(v[:2], 16), int(v[2:4], 16), int(v[4:6], 16)

def int_to_hex_color(v):
    assert(len(v) == 3)
    return '#%02x%02x%02x' % v