In Scala how do I remove duplicates from a list?

Question

Suppose I have

val dirty = List(\"a\", \"b\", \"a\", \"c\")

Is there a list operation that returns \"a\", \"b\", \"c\"

Answer 1

Have a look at the ScalaDoc for Seq,

scala> dirty.distinct
res0: List[java.lang.String] = List(a, b, c)

Update. Others have suggested using Set rather than List. That's fine, but be aware that by default, the Set interface doesn't preserve element order. You may want to use a Set implementation that explicitly does preserve order, such as collection.mutable.LinkedHashSet.

Answer 2

inArr.distinct foreach println _