Fastest way to incrementally read a large file

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灰色年华
灰色年华 2020-12-13 20:13

When given a buffer of MAX_BUFFER_SIZE, and a file that far exceeds it, how can one:

  1. Read the file in blocks of MAX_BUFFER_SIZE?
  2. Do it as fast as poss
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  • 2020-12-13 20:47

    If you want to make your first example faster

    FileChannel inChannel = new FileInputStream(fileName).getChannel();
    ByteBuffer buffer = ByteBuffer.allocateDirect(CAPACITY);
    
    while(inChannel.read(buffer) > 0)
        buffer.clear(); // do something with the data and clear/compact it.
    
    inChannel.close();
    

    If you want it to be even faster.

    FileChannel inChannel = new RandomAccessFile(fileName, "r").getChannel();
    MappedByteBuffer buffer = inChannel.map(FileChannel.MapMode.READ_ONLY, 0, inChannel.size());
    // access the buffer as you wish.
    inChannel.close();
    

    This can take 10 - 20 micro-seconds for files up to 2 GB in size.

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  • 2020-12-13 21:01

    Assuming that you need to read the entire file into memory at once (as you're currently doing), neither reading smaller chunks nor NIO are going to help you here.

    In fact, you'd probably be best reading larger chunks - which your regular IO code is automatically doing for you.

    Your NIO code is currently slower, because you're only reading one byte at a time (using buffer.get();).

    If you want to process in chunks - for example, transferring between streams - here is a standard way of doing it without NIO:

    InputStream is = ...;
    OutputStream os = ...;
    
    byte buffer[] = new byte[1024];
    int read;
    while((read = is.read(buffer)) != -1){
        os.write(buffer, 0, read);
    }
    

    This uses a buffer size of only 1 KB, but can transfer an unlimited amount of data.

    (If you extend your answer with details of what you're actually looking to do at a functional level, I could further improve this to a better answer.)

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