Is there an easy way to convert properties with dot notation to json
I.E
server.host=foo.bar
server.port=1234
TO
{
Using lightbend config java library (https://github.com/lightbend/config)
String toHierarchicalJsonString(Properties props) {
com.typesafe.config.Config config = com.typesafe.config.ConfigFactory.parseProperties(props);
return config.root().render(com.typesafe.config.ConfigRenderOptions.concise());
}
Look at this https://github.com/nzakas/props2js. You can use it manually or fork and use in your project.
It is pretty easy, download and add to your lib: https://code.google.com/p/google-gson/
Gson gsonObj = new Gson();
String strJson = gsonObj.toJson(yourObject);
A little bit recursion and Gson :)
public void run() throws IOException {
Properties properties = ...;
Map<String, Object> map = new TreeMap<>();
for (Object key : properties.keySet()) {
List<String> keyList = Arrays.asList(((String) key).split("\\."));
Map<String, Object> valueMap = createTree(keyList, map);
String value = properties.getProperty((String) key);
value = StringEscapeUtils.unescapeHtml(value);
valueMap.put(keyList.get(keyList.size() - 1), value);
}
Gson gson = new GsonBuilder().setPrettyPrinting().create();
String json = gson.toJson(map);
System.out.println("Ready, converts " + properties.size() + " entries.");
}
@SuppressWarnings("unchecked")
private Map<String, Object> createTree(List<String> keys, Map<String, Object> map) {
Map<String, Object> valueMap = (Map<String, Object>) map.get(keys.get(0));
if (valueMap == null) {
valueMap = new HashMap<String, Object>();
}
map.put(keys.get(0), valueMap);
Map<String, Object> out = valueMap;
if (keys.size() > 2) {
out = createTree(keys.subList(1, keys.size()), valueMap);
}
return out;
}
Not the easy way, but I managed to do that using Gson
library. The result will be in the
jsonBundle
String. Here we getting the properties or bundles in this case:
final ResourceBundle bundle = ResourceBundle.getBundle("messages");
final Map<String, String> bundleMap = resourceBundleToMap(bundle);
final Type mapType = new TypeToken<Map<String, String>>(){}.getType();
final String jsonBundle = new GsonBuilder()
.registerTypeAdapter(mapType, new BundleMapSerializer())
.create()
.toJson(bundleMap, mapType);
For this implementation ResourceBundle
have to be converted to Map
containing String
as a key and String
as a value.
private static Map<String, String> resourceBundleToMap(final ResourceBundle bundle) {
final Map<String, String> bundleMap = new HashMap<>();
for (String key: bundle.keySet()) {
final String value = bundle.getString(key);
bundleMap.put(key, value);
}
return bundleMap;
}
I had to create custom JSONSerializer
using Gson
for Map<String, String>
:
public class BundleMapSerializer implements JsonSerializer<Map<String, String>> {
private static final Logger LOGGER = LoggerFactory.getLogger(BundleMapSerializer.class);
@Override
public JsonElement serialize(final Map<String, String> bundleMap, final Type typeOfSrc, final JsonSerializationContext context) {
final JsonObject resultJson = new JsonObject();
for (final String key: bundleMap.keySet()) {
try {
createFromBundleKey(resultJson, key, bundleMap.get(key));
} catch (final IOException e) {
LOGGER.error("Bundle map serialization exception: ", e);
}
}
return resultJson;
}
}
And here is the main logic of creating JSON:
public static JsonObject createFromBundleKey(final JsonObject resultJson, final String key, final String value) throws IOException {
if (!key.contains(".")) {
resultJson.addProperty(key, value);
return resultJson;
}
final String currentKey = firstKey(key);
if (currentKey != null) {
final String subRightKey = key.substring(currentKey.length() + 1, key.length());
final JsonObject childJson = getJsonIfExists(resultJson, currentKey);
resultJson.add(currentKey, createFromBundleKey(childJson, subRightKey, value));
}
return resultJson;
}
private static String firstKey(final String fullKey) {
final String[] splittedKey = fullKey.split("\\.");
return (splittedKey.length != 0) ? splittedKey[0] : fullKey;
}
private static JsonObject getJsonIfExists(final JsonObject parent, final String key) {
if (parent == null) {
LOGGER.warn("Parent json parameter is null!");
return null;
}
if (parent.get(key) != null && !(parent.get(key) instanceof JsonObject)) {
throw new IllegalArgumentException("Invalid key \'" + key + "\' for parent: " + parent + "\nKey can not be JSON object and property or array in one time");
}
if (parent.getAsJsonObject(key) != null) {
return parent.getAsJsonObject(key);
} else {
return new JsonObject();
}
}
In the end, if there were a key person.name.firstname
with value John
, it will be converted to such JSON
:
{
"person" : {
"name" : {
"firstname" : "John"
}
}
}
Hope this will help :)
just use org.json.JSONObject
constructor that receives a Map (which Properties extends):
JSONObject jsonProps = new JSONObject(properties);
jsonProps.toString();
If you don't already have the properties loaded you can do that from a file
Properties properties= new Properties();
File file = new File("/path/to/test.properties");
FileInputStream fileInput = new FileInputStream(file);
properties.load(fileInput);
If you want to do the reverse, and read a json string into a prop file you can use com.fasterxml.jackson.databind.ObjectMapper
:
HashMap<String,String> result = new ObjectMapper().readValue(jsonPropString, HashMap.class);
Properties props = new Properties();
props.putAll(result);