I am pretty new to all of this so this might be a noobie question.. but I am looking to find length of dictionary values... but I do not know how this can be done.
S
Lets do some experimentation, to see how we could get/interpret the length of different dict/array values in a dict.
create our test dict, see list and dict comprehensions:
>>> my_dict = {x:[i for i in range(x)] for x in range(4)}
>>> my_dict
{0: [], 1: [0], 2: [0, 1], 3: [0, 1, 2]}
Get the length of the value of a specific key:
>>> my_dict[3]
[0, 1, 2]
>>> len(my_dict[3])
3
Get a dict of the lengths of the values of each key:
>>> key_to_value_lengths = {k:len(v) for k, v in my_dict.items()}
{0: 0, 1: 1, 2: 2, 3: 3}
>>> key_to_value_lengths[2]
2
Get the sum of the lengths of all values in the dict:
>>> [len(x) for x in my_dict.values()]
[0, 1, 2, 3]
>>> sum([len(x) for x in my_dict.values()])
6
A common use case I have is a dictionary of numpy arrays or lists where I know they're all the same length, and I just need to know one of them (e.g. I'm plotting timeseries data and each timeseries has the same number of timesteps). I often use this:
length = len(next(iter(d.values())))
Let dictionary be :
dict={key:['value1','value2']}
If you know the key :
print(len(dict[key]))
else :
val=[len(i) for i in dict.values()]
print(val[0])
# for printing length of 1st key value or length of values in keys if all keys have same amount of values.
To find all of the lengths of the values in a dictionary you can do this:
lengths = [len(v) for v in d.values()]
d={1:'a',2:'b'}
sum=0
for i in range(0,len(d),1):
sum=sum+1
i=i+1
print i
OUTPUT=2
Sure. In this case, you'd just do:
length_key = len(d['key']) # length of the list stored at `'key'` ...
It's hard to say why you actually want this, but, perhaps it would be useful to create another dict that maps the keys to the length of values:
length_dict = {key: len(value) for key, value in d.items()}
length_key = length_dict['key'] # length of the list stored at `'key'` ...