How to read lines from stdin (*in*) in clojure

Question

I am writing my first clojure program, and want to read lines from stdin.

When I try this:

(doall (map #(println %) (line-seq *in*)))

Answer 1

Try wrapping *in* in a java.io.BufferedReader. And also use doseq instead of doall, as devstopfix pointed out:

(doseq [ln (line-seq (java.io.BufferedReader. *in*))]
   (println ln))

Note that line-seq is documented to require a BufferedReader as its source.

Answer 2

You should probably use doseq instead of doall:

(doseq [line (line-seq (java.io.BufferedReader. *in*))] 
    (println line))

doall:

Walks through the successive nexts of the seq, retains the head and returns it, thus causing the entire seq to reside in memory at one time.

doseq:

Does not retain the head of the sequence. Returns nil.

Answer 3

For reasonably small inputs, the following would also work:

(let [input-string (slurp *in*)]
  (println input-string))

Or, splitting by lines:

(let [lines (clojure.string/split-lines (slurp *in*))]
  (println lines))

Answer 4

Just a note that for anyone who wants to only read a single line, there's the read-line function.