Read JSON file with Swift 3

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余生分开走
余生分开走 2020-12-13 13:15

I have a JSON file called points.json, and a read function like:

private func readJson() {
    let file = Bundle.main.path(forResource: \"points\",          


        
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  • 2020-12-13 13:19

    Your problem here is that you force unwrap the values and in case of an error you can't know where it comes from.

    Instead, you should handle errors and safely unwrap your optionals.

    And as @vadian rightly notes in his comment, you should use Bundle.main.url.

    private func readJson() {
        do {
            if let file = Bundle.main.url(forResource: "points", withExtension: "json") {
                let data = try Data(contentsOf: file)
                let json = try JSONSerialization.jsonObject(with: data, options: [])
                if let object = json as? [String: Any] {
                    // json is a dictionary
                    print(object)
                } else if let object = json as? [Any] {
                    // json is an array
                    print(object)
                } else {
                    print("JSON is invalid")
                }
            } else {
                print("no file")
            }
        } catch {
            print(error.localizedDescription)
        }
    }
    

    When coding in Swift, usually, ! is a code smell. Of course there's exceptions (IBOutlets and others) but try to not use force unwrapping with ! yourself and always unwrap safely instead.

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  • 2020-12-13 13:22

    The Swift 5 / iOS 12.3 code below shows a possible rewrite of your method that avoids force unwrap on optional values and handles gently potential errors:

    import Foundation
    
    func readJson() {
        // Get url for file
        guard let fileUrl = Bundle.main.url(forResource: "Data", withExtension: "json") else {
            print("File could not be located at the given url")
            return
        }
    
        do {
            // Get data from file
            let data = try Data(contentsOf: fileUrl)
    
            // Decode data to a Dictionary<String, Any> object
            guard let dictionary = try JSONSerialization.jsonObject(with: data, options: []) as? [String: Any] else {
                print("Could not cast JSON content as a Dictionary<String, Any>")
                return
            }
    
            // Print result
            print(dictionary)
        } catch {
            // Print error if something went wrong
            print("Error: \(error)")
        }
    }
    
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