/bin/sh: pushd: not found

Question

I am doing the following inside a make file

pushd %dir_name%

and i get the following error

/bin/sh : pushd : not foun         


        

Answer 1

here is a method to point

sh -> bash

run this command on terminal

sudo dpkg-reconfigure dash

After this you should see

ls -l /bin/sh

point to /bin/bash (and not to /bin/dash)

Reference

Answer 2

pushd is a bash enhancement to the POSIX-specified Bourne Shell. pushd cannot be easily implemented as a command, because the current working directory is a feature of a process that cannot be changed by child processes. (A hypothetical pushd command might do the chdir(2) call and then start a new shell, but ... it wouldn't be very usable.) pushd is a shell builtin, just like cd.

So, either change your script to start with #!/bin/bash or store the current working directory in a variable, do your work, then change back. Depends if you want a shell script that works on very reduced systems (say, a Debian build server) or if you're fine always requiring bash.

Answer 3

Run "apt install bash" It will install everything you need and the command will work

Answer 4

This ought to do the trick:

( cd dirname ; pwd ); pwd

The parentheses start a new child shell, thus the cd changes the directory within the child only, and any command after it within the parentheses will run in that folder. Once you exit the parentheses you are back in wherever you were before..

Answer 5

A workaround for this would be to have a variable get the current working directory. Then you can cd out of it to do whatever, then when you need it, you can cd back in.

i.e.

oldpath=`pwd`
#do whatever your script does
...
...
...
# go back to the dir you wanted to pushd
cd $oldpath

Answer 6

This is because pushd is a builtin function in bash. So it is not related to the PATH variable and also it is not supported by /bin/sh (which is used by default by make. You can change that by setting SHELL (although it will not work directly (test1)).

You can instead run all the commands through bash -c "...". That will make the commands, including pushd/popd, run in a bash environment (test2).

SHELL = /bin/bash

test1:
        @echo before
        @pwd
        @pushd /tmp
        @echo in /tmp
        @pwd
        @popd
        @echo after
        @pwd

test2:
        @/bin/bash -c "echo before;\
        pwd; \
        pushd /tmp; \
        echo in /tmp; \
        pwd; \
        popd; \
        echo after; \
        pwd;"

When running make test1 and make test2 it gives the following:

prompt>make test1
before
/download/2011/03_mar
make: pushd: Command not found
make: *** [test1] Error 127
prompt>make test2
before
/download/2011/03_mar
/tmp /download/2011/03_mar
in /tmp
/tmp
/download/2011/03_mar
after
/download/2011/03_mar
prompt>

For test1, even though bash is used as a shell, each command/line in the rule is run by itself, so the pushd command is run in a different shell than the popd.