Get name of executable jar from within main() method [duplicate]

Answer 1

Here you go:

new java.io.File(SomeClassInYourJar.class.getProtectionDomain()
  .getCodeSource()
  .getLocation()
  .getPath())
.getName()

Edit: I saw your comment about getSourceCode API. Well, this is probably the best you can do in Java. About getCodeSource() returning null, I think it mainly happens on classes in java.lang.* and other special classes for which the source location is "hidden". Should work for your own classes though.

Answer 2

You should in any case add a .toURI() before you call getPath(). Thats because of some quirks in java's URL implementation - see how to encode URL to avoid special characters in java for details.