I\'m trying to create a simple program that tells you your lucky number according to numerology. I keep on getting this error:
File \"number.py\", line 12, i
Just to be clear, all the answers so far are correct, but the reasoning behind them is not explained very well.
The sumall
variable is not yet a string. Parentheticals will not convert to a string (e.g. summ = (int(birthday[0])+int(birthday[1]))
still returns an integer. It looks like you most likely intended to type str((int(sumall[0])+int(sumall[1])))
, but forgot to. The reason the str()
function fixes everything is because it converts anything in it compatible to a string.
You can't do something like that: (int(sumall[0])+int(sumall[1]))
That's because sumall
is an int
and not a list or dict.
So, summ + sumd
will be you're lucky number
sumall = summ + sumd + sumy
Your sumall
is an integer. If you want the individual characters from it, convert it to a string first.
Try this instead:
sumall = summ + sumd + sumy
print "The sum of your numbers is", sumall
sumall = str(sumall) # add this line
sumln = (int(sumall[0])+int(sumall[1]))
print "Your lucky number is", sumln
sumall
is a number, and you can't access its digits using the subscript notation (sumall[0]
, sumall[1]
). For that to work, you'll need to transform it back to a string.
The error is exactly what it says it is; you're trying to take sumall[0]
when sumall
is an int and that doesn't make any sense. What do you believe sumall
should be?
If you want to sum the digit of a number, one way to do it is using sum() + a generator expression:
sum(int(i) for i in str(155))
I modified a little your code using sum()
, maybe you want to take a look at it:
birthday = raw_input("When is your birthday(mm/dd/yyyy)? ")
summ = sum(int(i) for i in birthday[0:2])
sumd = sum(int(i) for i in birthday[3:5])
sumy = sum(int(i) for i in birthday[6:10])
sumall = summ + sumd + sumy
print "The sum of your numbers is", sumall
sumln = sum(int(c) for c in str(sumall)))
print "Your lucky number is", sumln