Java interpreter? [closed]

Answer 1

Don't forget Jython

Edited answer:

True, it is not an interpreter as in the sense of the question, so a fair downvote. But IMO, it's possible to throw "some" Java code towards it, and it'll output the result:

>>> from java.lang import System
>>> System.out.println("Hello world")
Hello world
>>> from java.util import Random
>>> r = Random()
>>> r.nextInt()
572839857
>>> r.nextInt(2)
0

I just believe that a smart developer would be able to make quite efficient use of this. I know it's helped me in the past :)

Answer 2

Your best bet is probably http://www.javarepl.com/ but there are several other options:

If you require the interpreter to support Java syntax exactly, then ideone.com will let you evaluate arbitrary Java code.

If you want to evaluate Java snippets, you could use a Groovy interpreter. Java code is generally valid Groovy too, and Groovy doesn't force you to define a whole class. There's an online Groovy interpreter.

If you don't require the interpreter to be online, there's also the Eclipse scrap book, DrJava, and BeanShell2 which all allow Java to be interpreted.

Answer 3

Use bsh. It's a java-based shell.

Answer 4

Check out Ideone.com. You can type in a Java program and it'll compile it and then run it for you and display the output. Here's a hello world example I just typed in.

Code:

public class Main {
    public void main(String[] arguments) {
        System.out.println("Hello world!");
    }
}

Output:

result: success   time: 0.1s   memory: 213376 kB   returned value: 1

input: no
output: no
stderr:
Exception in thread "main" java.lang.NoSuchMethodError: main

Oops, I forgot to declare main as static!