Sort pandas dataframe both on values of a column and index?

Question

Is it feasible to sort pandas dataframe by values of a column, but also by index?

If you sort a pandas dataframe by values of a column, you can get the resultant dat

Answer 1

I believe that the original order from sort_values is kept even when sort_index is applied, so this should work:

df.sort_values('count', ascending=False).sort_index(level=[index_level1, index_level2])

Answer 2

You can use a combination of groupby and apply:

In [2]: df = pd.DataFrame({
            'transID':  range(8),
            'Location': ['New York','Chicago','New York','New York','Atlanta','Los Angeles',
                            'Chicago','Atlanta'],
            'Sales':    np.random.randint(0,10000,8)}).set_index('transID')
In [3]: df
Out[3]:
        Location    Sales
transID
0       New York    1082
1       Chicago     1664
2       New York    692
3       New York    5669
4       Atlanta     7715
5       Los Angeles 987
6       Chicago     4085
7       Atlanta     2927

In [4]: df.groupby('Location').apply(lambda d: d.sort()).reset_index('Location',drop=True)
Out[4]:
        Location    Sales
transID
4       Atlanta     7715
7       Atlanta     2927
1       Chicago     1664
6       Chicago     4085
5       Los Angeles 987
0       New York    1082
2       New York    692
3       New York    5669

I drop 'Location' at in the last line because groupby inserts the grouped levels into the first positions in the index. Sorting and then dropping them preserves the sorted order.