I\'m Trying to get the timediff from my table and convert it to hours (it\'s for an hourly billed service)
SELECT TIME_TO_SEC(TIMEDIFF(endDate,startDa
NOTE the most voted up answer in this chain is INCORRECT! Using HOUR will only return hours as an integer. Below would correct the most popular answer to return hours as an integer and minutes as a decimal (ie 6.5 hours).
TIME_TO_SEC(TIMEDIFF(endDate, startDate))/3600 as hours
TIMEDIFF(endDate, startDate)
outputs in DateTime format, so flat that to timestamp and devide by (60*60)
SELECT (UNIX_TIMESTAMP(TIMEDIFF(endDate, startDate))/(60*60)) AS hours_difference
FROM tasks
Edit: Alternatively,TimestampDiff may also provide a valid solution in more elegant way providing its example:
SELECT TIMESTAMPDIFF(MONTH,'2003-02-01','2003-05-01');
And your solution can be:
SELECT TIMESTAMPDIFF(HOUR, startDate, endDate) AS hours_different
FROM tasks
TIMEDIFF(endDate, startDate) / 10000
You can use UNIX_TIMESTAMP to do the calculation in SELECT query.
SELECT (UNIX_TIMESTAMP(endDate)-UNIX_TIMESTAMP(startDate))/3600 hour_diff
FROM tasks
UNIX_TIMESTAMP convert datetime to number of second from epoch. You can substract both timestamp to get difference in second. Divide it with 3600 will give you difference in hour.
eg: startDate 2010-01-31 00:00:00, endDate 2010-01-31 19:24:22
SELECT (UNIX_TIMESTAMP(dateFin)-UNIX_TIMESTAMP(dateDebut))/3600 hour_diff
FROM tasks
SELECT TIME_TO_SEC(TIMEDIFF(endDate,startDate))/3600
FROM tasks
returns 19.4061 which is good
SELECT TIMESTAMPDIFF(HOUR, endDate, startDate) AS hours_different
FROM tasks
Only returns hours while i also need minutes to be converted.
SELECT (UNIX_TIMESTAMP(TIMEDIFF(endDate, startDate))/(60*60)) AS hours_difference
FROM tasks
returns 0. I think the first one is the most efficent. Thanks !!
TIMESTAMPDIFF(HOUR, startDate, endDate)
is the best way to do it, because it works with big time intervals, like
TIMESTAMPDIFF(HOUR, "2012-01-01 00:00:00", "2050-01-01 00:00:00")
Result: 333120
while
HOUR(TIMEDIFF("2050-01-01 00:00:00", "2012-01-01 00:00:00"))
Result: 838
fails.
As we see in the example above, it surprisingly even works beyond the timestamp limitation in year 2038.
The maximum hours which are returned by HOUR(TIMEDIFF(dateEnd, dateStart))
is 838, because TIMEDIFF
is limited to the range allowed for TIME
values.