A PostgreSQL query with 'ANY' is not working

Question

SELECT \"Ticket_id\"  FROM \"Tickets\"
 WHERE \"Status\" = 1 AND (\"Ticket_id\" !=  ANY(array[1,2,3])) Limit 6

And the result is 1,2,3,4,5,6

Answer 1

You want to use ALL, not ANY. From the fine manual:

9.21.3. ANY/SOME (array)

expression operator ANY (array expression)

[...] The left-hand expression is evaluated and compared to each element of the array using the given operator, which must yield a Boolean result. The result of ANY is "true" if any true result is obtained.

So if we say this:

1 != any(array[1,2])

then we'll get true since (1 != 1) or (1 != 2) is true. ANY is essentially an OR operator. For example:

=> select id from (values (1),(2),(3)) as t(id) where id != any(array[1,2]);
 id 
----
  1
  2
  3
(3 rows)

If we look at ALL, we see:

9.21.4. ALL (array)

expression operator ALL (array expression)

[...] The left-hand expression is evaluated and compared to each element of the array using the given operator, which must yield a Boolean result. The result of ALL is "true" if all comparisons yield true...

so if we say this:

1 != all(array[1,2])

then we'll get false since (1 != 1) and (1 != 2) is false and we see that ALL is essentially an AND operator. For example:

=> select id from (values (1),(2),(3)) as t(id) where id != all(array[1,2]);
 id 
----
  3
(1 row)

If you want to exclude all values in an array, use ALL:

select "Ticket_id"
from "Tickets"
where "Status" = 1
  and "Ticket_id" != all(array[1,2,3])
limit 6

Answer 2

Do you mean:

"Ticked_id" NOT IN (1,2,3)