What does Post.all.map(&:id) mean? [duplicate]

Answer 1

The & symbol is used to denote that the following argument should be treated as the block given to the method. That means that if it's not a Proc object yet, its to_proc method will be called to transform it into one.

Thus, your example results in something like

Post.all.map(&:id.to_proc)

which in turn is equivalent to

Post.all.map { |x| x.id }

So it iterates over the collection returned by Post.all and builds up an array with the result of the id method called on every item.

This works because Symbol#to_proc creates a Proc that takes an object and calls the method with the name of the symbol on it. It's mainly used for convenience, to save some typing.

Answer 2

It is a Ruby trick, which relies on Ruby doing some dynamic type conversion. You can find an explanation of the Symbol#to_proc trick here.

Answer 3

This takes all Post objects and creates an array with the id method being invoked on each one.

In other words, for ActiveRecord, this means that you are getting an array with the id attribute for all Post entities in your database.

Answer 4

& means that you are passing a block

Post.all is the receiver of the method .map, and its block is being passed on

Post.all.map { |item| # do something }

http://ruby-doc.org/core-1.9.3/Enumerable.html#method-i-map

It iterates over the array and create a lambda with symbol#to_proc

http://ruby-doc.org/core-1.9.3/Symbol.html#method-i-to_proc