What is the equivalent of javascript setTimeout in Java?

前端 未结 9 870
梦毁少年i
梦毁少年i 2020-12-13 06:23

I need to implement a function to run after 60 seconds of clicking a button. Please help, I used the Timer class, but I think that that is not the best way.

相关标签:
9条回答
  • 2020-12-13 06:34

    Asynchronous implementation with JDK 1.8:

    public static void setTimeout(Runnable runnable, int delay){
        new Thread(() -> {
            try {
                Thread.sleep(delay);
                runnable.run();
            }
            catch (Exception e){
                System.err.println(e);
            }
        }).start();
    }
    

    To call with lambda expression:

    setTimeout(() -> System.out.println("test"), 1000);
    

    Or with method reference:

    setTimeout(anInstance::aMethod, 1000);
    

    To deal with the current running thread only use a synchronous version:

    public static void setTimeoutSync(Runnable runnable, int delay) {
        try {
            Thread.sleep(delay);
            runnable.run();
        }
        catch (Exception e){
            System.err.println(e);
        }
    }
    

    Use this with caution in main thread – it will suspend everything after the call until timeout expires and runnable executes.

    0 讨论(0)
  • 2020-12-13 06:35

    You can simply use Thread.sleep() for this purpose. But if you are working in a multithreaded environment with a user interface, you would want to perform this in the separate thread to avoid the sleep to block the user interface.

    try{
        Thread.sleep(60000);
        // Then do something meaningful...
    }catch(InterruptedException e){
        e.printStackTrace();
    }
    
    0 讨论(0)
  • 2020-12-13 06:37

    Use Java 9 CompletableFuture, every simple:

    CompletableFuture.delayedExecutor(5, TimeUnit.SECONDS).execute(() -> {
      // Your code here executes after 5 seconds!
    });
    
    0 讨论(0)
  • 2020-12-13 06:38

    "I used the Timer class, but I think that that is not the best way."

    The other answers assume you are not using Swing for your user interface (button).

    If you are using Swing then do not use Thread.sleep() as it will freeze your Swing application.

    Instead you should use a javax.swing.Timer.

    See the Java tutorial How to Use Swing Timers and Lesson: Concurrency in Swing for more information and examples.

    0 讨论(0)
  • 2020-12-13 06:42

    Do not use Thread.sleep or it will freeze your main thread and not simulate setTimeout from JS. You need to create and start a new background thread to run your code without stoping the execution of the main thread. Like this:

    new Thread() {
        @Override
        public void run() {
            try {
                this.sleep(3000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
    
    
            // your code here
    
        }
    }.start();
    
    0 讨论(0)
  • 2020-12-13 06:50

    There is setTimeout() method in underscore-java library.

    Code example:

    import com.github.underscore.U;
    import com.github.underscore.Function;
    
    public class Main {
    
        public static void main(String[] args) {
            final Integer[] counter = new Integer[] {0};
            Function<Void> incr = new Function<Void>() { public Void apply() {
                counter[0]++; return null; } };
            U.setTimeout(incr, 100);
        }
    }
    

    The function will be started in 100ms with a new thread.

    0 讨论(0)
提交回复
热议问题