Is there a fast way to check if one set entirely contains another?
Something like:
>>>[1, 2, 3].containsAll([2, 1]) True >>>[1, 2,
Those are lists, but if you really mean sets you can use the issubset method.
>>> s = set([1,2,3]) >>> t = set([1,2]) >>> t.issubset(s) True >>> s.issuperset(t) True
For a list, you will not be able to do better than checking each element.