How to compare two strings ignoring case in Swift language?

Question

How can we compare two strings in swift ignoring case ? for eg :

var a = \"Cash\"
var b = \"cash\"

Is there any method that will return tru

Answer 1

Try this:

var a = "Cash"
var b = "cash"
let result: NSComparisonResult = a.compare(b, options: NSStringCompareOptions.CaseInsensitiveSearch, range: nil, locale: nil)

// You can also ignore last two parameters(thanks 0x7fffffff)
//let result: NSComparisonResult = a.compare(b, options: NSStringCompareOptions.CaseInsensitiveSearch)

result is type of NSComparisonResult enum:

enum NSComparisonResult : Int {

    case OrderedAscending
    case OrderedSame
    case OrderedDescending
}

So you can use if statement:

if result == .OrderedSame {
    println("equal")
} else {
    println("not equal")
}

Answer 2

Use caseInsensitiveCompare method:

let a = "Cash"
let b = "cash"
let c = a.caseInsensitiveCompare(b) == .orderedSame
print(c) // "true"

ComparisonResult tells you which word comes earlier than the other in lexicographic order (i.e. which one comes closer to the front of a dictionary). .orderedSame means the strings would end up in the same spot in the dictionary

Answer 3

if a.lowercaseString == b.lowercaseString {
    //Strings match
}

Answer 4

Could just roll your own:

func equalIgnoringCase(a:String, b:String) -> Bool {
    return a.lowercaseString == b.lowercaseString
}

Answer 5

For Swift 5 Ignoring the case and compare two string

var a = "cash"
var b = "Cash"
if(a.caseInsensitiveCompare(b) == .orderedSame){
     print("Ok")
}

Answer 6

Swift 3

if a.lowercased() == b.lowercased() {

}