What is the equivalent of this SQL statement in django?
SELECT * FROM table_name WHERE string LIKE pattern;
How do I implement this in djan
Use __contains or __icontains (case-insensitive):
result = table.objects.filter(string__contains='pattern')
The SQL equivalent is
SELECT ... WHERE string LIKE '%pattern%';
This can be done with Django's custom lookups. I have made the lookup into a Django-like-lookup application. After installing it the __like
lookup with the %
and _
wildcards will be enabled.
All the necessary code in the application is:
from django.db.models import Lookup
from django.db.models.fields import Field
@Field.register_lookup
class Like(Lookup):
lookup_name = 'like'
def as_sql(self, compiler, connection):
lhs, lhs_params = self.process_lhs(compiler, connection)
rhs, rhs_params = self.process_rhs(compiler, connection)
params = lhs_params + rhs_params
return '%s LIKE %s' % (lhs, rhs), params
result = table.objects.filter(string__icontains='pattern')
Case insensitive search for string in a field.
contains and icontains mentioned by falsetru make queries like SELECT ... WHERE headline LIKE '%pattern%
Along with them, you might need these ones with similar behavior: startswith, istartswith, endswith, iendswith
making
SELECT ... WHERE headline LIKE 'pattern%
or
SELECT ... WHERE headline LIKE '%pattern
In order to preserve the order of the words as in the sql LIKE '%pattern%' statement I use iregex, for example:
qs = table.objects.filter(string__iregex=pattern.replace(' ', '.*'))
string methods are immutable so your pattern variable will not change and with .* you'll be looking for 0 or more occurrences of any character but break lines.
By using the following to iterate over the pattern words:
qs = table.objects
for word in pattern.split(' '):
qs = qs.filter(string__icontains=word)
the order of the words in your pattern will not be preserved, for some people that could work but in the case of trying to mimic the sql like statement I'll use the first option.