I want to make clear when does pipe | or redirection < > takes precedence in a command?
This is my thought but need confirmation this is how it works.
Exa
From man bash (as are the other quotes):
SHELL GRAMMAR
Simple Commands
A simple command is a sequence of optional variable assignments followed by
blank-separated words and redirections, and terminated by a control
operator. The first word specifies the command to be executed, and is
passed as argument zero. The remaining words are passed as arguments
to the invoked command.
The return value of a simple command is its exit status, or 128+n if
the command is terminated by signal n.
Pipelines
A pipeline is a sequence of one or more commands separated by one of
the control operators | or |&. The format for a pipeline is:
[time [-p]] [ ! ] command [ [|⎪|&] command2 ... ]
In other words, you can have any number of redirections for a (simple) command; you can also use that as part of a pipeline. Or, put another way, redirection binds more tightly than pipe.
There are a couple of ways to get work around this (although they're rarely either necessary or aesthetic):
1. You can make a "compound command" and redirect into it:
Compound Commands
A compound command is one of the following:
(list) list is executed in a subshell environment (see
COMMAND EXECUTION ENVIRONMENT below). Variable
assignments and builtin commands that affect the
shell's environment do not remain in effect after the
command completes. The return status is the exit status of list.
{ list; }
list is simply executed in the current shell environment. list
must be terminated with a newline or semicolon. This is known as a
group command. The return status is the exit status of list. Note
that unlike the metacharacters ( and ), { and } are reserved words
and must occur where a reserved word is permitted to be recognized.
Since they do not cause a word break, they must be separated from
list by whitespace or another shell metacharacter.
So:
$ echo foo > input
$ { cat | sed 's/^/I saw a line: /'; } < input
I saw a line: foo
2. You can redirect to a pipe using "process substitution":
Process Substitution
Process substitution is supported on systems that support named pipes
(FIFOs) or the /dev/fd method of naming open files. It takes the form of
<(list) or >(list). The process list is run with its input or output
connected to a FIFO or some file in /dev/fd. The name of this file is
passed as an argument to the current command as the result of the
expansion. If the >(list) form is used, writing to the file will provide
input for list. If the <(list) form is used, the file passed as an argument
should be read to obtain the output of list.
So:
rici@...$ cat > >(sed 's/^/I saw a line: /') < <(echo foo; echo bar)
I saw a line: foo
rici@...$ I saw a line: bar
(Why the prompt appears before the output terminates, and what to do about it are left as exercises).
It's a little unorthodox, but perfectly legal, to place the < anywhere you like, so I prefer this as it better illustrates the left-to-right data flow:
<input.txt sort | head >output.txt
The only time you cannot do this is with built-in control structure commands (for, if, while).
# Unfortunately, NOT LEGAL
<input.txt while read line; do ...; done
Note that all of these are equivalent commands, but to avoid confusion you should use only the first or the last one:
<input.txt grep -l foobar
grep <input.txt -l foobar
grep -l <input.txt foobar
grep -l foobar <input.txt
Because the file name must always come directly after the redirection operator, I prefer to leave out the optional space between the < and the file name.
In terms of syntactic grouping, > and < have higher precedence; that is, these two commands are equivalent:
sort < names | head
( sort < names ) | head
as are these two:
ls | sort > out.txt
ls | ( sort > out.txt )
But in terms of sequential ordering, | is performed first; so, this command:
cat in.txt > out1.txt | cat > out2.txt
will populate out1.txt, not out2.txt, because the > out1.txt is performed after the |, and therefore supersedes it (so no output is piped out to cat > out2.txt).
Similarly, this command:
cat < in1.txt | cat < in2.txt
will print in2.txt, not in1.txt, because the < in2.txt is performed after the |, and therefore supersedes it (so no input is piped in from cat < in1.txt).
Corrections:
Example 1:
sort < names | head
In this case, input redirect runs first (names are sorted), then the result of that is piped to head.
In general you can read from left to right. The standard idiom works as follows:
This is pretty much what I understand after doing some reading (including ruakh's answer)
First of all, if you redirect multiple times, all the redirections are performed, but only the last redirection will take effect (assuming none of the earlier redirections cause error)
e.g. cat < in1.txt < in2.txt is equivalent to cat < in2.txt, unless in1.txt does not exist in which case this command will fail (since < in1.txt is performed first)
Similarly, with cat in.txt > out1.txt > out2.txt, only out2.txt would contain the contents of out2.txt, but since > out1.txt was performed first, out1.txt would be created if it doesn't exist.
What pipe does is connect the stdout of previous command to the stdin of the next command, and that connection comes before any other redirections (from Bash manual).
So you can think of
cat in1.txt > out1.txt | cat > out2.txt
as
cat in1.txt > pipe > out1.txt; cat < pipe > out2.txt
And applying the multiple redirection rule mentioned before, we can simplify this to
cat in1.txt > out1.txt; cat < pipe > out2.txt
Result: The content of in1.txt is copied to out1.txt, since nothing was written to pipe
cat < in1.txt | cat > in2.txt
is roughly equivalent to
cat > pipe < in1.txt; cat < pipe < in2.txt
which is effectively
cat > pipe < in1.txt; cat < in2.txt
Result: This time something is written to the pipe, but since the second cat reads from in2.txt instead of pipe, only the content of in2.txt is printed out.