C++ member function virtual override and overload at the same time

Question

If I have a code like this:

struct A {
  virtual void f(int) {}
  virtual void f(void*) {}
};

struct B : public A {
  void f(int) {}
};

struct C : public B         


        

Answer 1

Or you could do this:

void main()
{
    A *a = new C();
    a->f(1);  //This will call f(int) from B(Polymorphism)
}

Answer 2

The short answer is "because that's how overload resolution works in C++".

The compiler searches for functions F inside the C class, and if it finds any, it stops the search, and tries to pick a candidate among those. It only looks inside base classes if no matching functions were found in the derived class.

However, you can explicitly introduce the base class functions into the derived class' namespace:

struct C : public B {
  void f(void*) {}
  using B::f; // Add B's f function to C's namespace, allowing it to participate in overload resolution
};

Answer 3

Well I think first of all you did not understand what virtual mechanism or polymorhism. When the polymorphism is achieved only by using object pointers. I think you are new to c++. Without using object pointers then there is no meaning of polymorphism or virtual keyword use base class pointer and assign the desired derived class objects to it. Then call and try it.