pass output as an argument for cp in bash [duplicate]

Answer 1

I would do:

cp $(ls -SF | grep -v / | head -5) Directory

xargs would probably be the best answer though.

ls -SF | grep -v / | head -5 | xargs -I{} cp "{}" Directory

Answer 2

If your cp has a "-t" flag (check the man page), that simplifies matters a bit:

ls -SF | grep -v / | head -5 | xargs cp -t DIRECTORY

The find command gives you more fine-grained ability to get what you want, instead of ls | grep that you have. I'd code your question like this:

find . -maxdepth 1 -type f -printf "%p\t%s\n" | 
sort -t $'\t' -k2 -nr | 
head -n 5 | 
cut -f 1 | 
xargs echo cp -t DIRECTORY

Answer 3

Use backticks `like this` or the dollar sign $(like this) to perform command substitution. Basically this pastes each line of standard ouput of the backticked command into the surrounding command and runs it. Find out more in the bash manpage under "Command Substitution."

Also, if you want to read one line at a time you can read individual lines out of a pipe stream using "while read" syntax:

ls | while read varname; do echo $varname; done

Answer 4

It would be:

cp `ls -SF | grep -v / | head -5` Directory

assuming that the pipeline is correct. The backticks substitute in the line the output of the commands inside it.

You can also make your tests:

cp `echo a b c` Directory

will copy all a, b, and c into Directory.