How can I create custom page for django admin?

Question

I want to create custom page for admin panel without model. For first i copy index.html to project folder:

mysite/
    templates/
        admin/
                     


        

Answer 1

Years go by and still a relevant answer to this can be posted.

Using Django 1.10+ you can do:

security/admin.py (this is your app's admin file)

from django.contrib import admin
from django.conf.urls import url
from django.template.response import TemplateResponse
from security.models import Security


@admin.register(Security)
class SecurityAdmin(admin.ModelAdmin):

    def get_urls(self):

        # get the default urls
        urls = super(SecurityAdmin, self).get_urls()

        # define security urls
        security_urls = [
            url(r'^configuration/$', self.admin_site.admin_view(self.security_configuration))
            # Add here more urls if you want following same logic
        ]

        # Make sure here you place your added urls first than the admin default urls
        return security_urls + urls

    # Your view definition fn
    def security_configuration(self, request):
        context = dict(
            self.admin_site.each_context(request), # Include common variables for rendering the admin template.
            something="test",
        )
        return TemplateResponse(request, "configuration.html", context)

security/templates/configuration.html

{% extends "admin/base_site.html" %}
{% block content %}
...
{% endblock %}

See Official ModelAdmin.get_urls description (make sure you select proper Django version, this code is valid for 1.10 above)

• Note the use of get_urls() above.
• This new admin page will be accessible under: https://localhost:8000/admin/security/configuration/
• This page will be protected under admin login area

Answer 2

You need to add your admin URL before the URL patterns of the admin itself:

urlpatterns = patterns('',
   url(r'^admin/preferences/$', TemplateView.as_view(template_name='admin/preferences/preferences.html')),
   url(r'^admin/', include('django.contrib.admin.urls')),
)

This way the URL won't be processed by Django's admin.

Answer 3

You should be using admin's get_urls.

Answer 4

Here's an example of everything that should be needed (as of Django 1.6) for a custom admin page that is linked to from a button next to the "History" button in the top right of an object's detail page:

https://gist.github.com/mattlong/4b64212e096766e058b7

Answer 5

Full example:

from django.conf.urls import url
from django.contrib import admin
from django.db import models

class DummyModel(models.Model):
    class Meta:
        verbose_name = 'Link to my shiny custom view'
        app_label = 'users'  # or another app to put your custom view

@admin.register(DummyModel)
class DummyModelAdmin(admin.ModelAdmin):
    def get_urls(self):
        view_name = '{}_{}_changelist'.format(
                DummyModel._meta.app_label, DummyModel._meta.model_name)
        return [
            url(r'^my_view/$', MyCustomView.as_view(), name=view_name)
        ]

With this approach Django's makemigrations command will create DB migration to create table for DummyModel.