Split string by single spaces [duplicate]

Answer 1

You can even develop your own split function (I know, little old-fashioned):

size_t split(const std::string &txt, std::vector<std::string> &strs, char ch)
{
    size_t pos = txt.find( ch );
    size_t initialPos = 0;
    strs.clear();

    // Decompose statement
    while( pos != std::string::npos ) {
        strs.push_back( txt.substr( initialPos, pos - initialPos ) );
        initialPos = pos + 1;

        pos = txt.find( ch, initialPos );
    }

    // Add the last one
    strs.push_back( txt.substr( initialPos, std::min( pos, txt.size() ) - initialPos + 1 ) );

    return strs.size();
}

Then you just need to invoke it with a vector<string> as argument:

int main()
{
    std::vector<std::string> v;

    split( "This  is a  test", v, ' ' );
    dump( cout, v );

    return 0;
}

Find the code for splitting a string in IDEone.

Hope this helps.

Answer 2

You could used simple strtok() function (*)From here. Note that tokens are created on delimiters

#include <stdio.h>
#include <string.h>

int main ()
{
  char str[] ="- This is a string";
  char * pch;
  printf ("Splitting string \"%s\" into tokens:\n",str);
  pch = strtok (str," ,.-");
  while (pch != NULL)
  {
    printf ("%s\n",pch);
    pch = strtok (NULL, " ,.-");
  }
  return 0;
}

Answer 3

If you are averse to boost, you can use regular old operator>>, along with std::noskipws:

EDIT: updates after testing.

#include <iostream>
#include <iomanip>
#include <vector>
#include <string>
#include <algorithm>
#include <iterator>
#include <sstream>

void split(const std::string& str, std::vector<std::string>& v) {
  std::stringstream ss(str);
  ss >> std::noskipws;
  std::string field;
  char ws_delim;
  while(1) {
    if( ss >> field )
      v.push_back(field);
    else if (ss.eof())
      break;
    else
      v.push_back(std::string());
    ss.clear();
    ss >> ws_delim;
  }
}

int main() {
  std::vector<std::string> v;
  split("hello world  how are   you", v);
  std::copy(v.begin(), v.end(), std::ostream_iterator<std::string>(std::cout, "-"));
  std::cout << "\n";
}

http://ideone.com/62McC

Answer 4

If strictly one space character is the delimiter, probably std::getline will be valid.
For example:

int main() {
  using namespace std;
  istringstream iss("This  is a string");
  string s;
  while ( getline( iss, s, ' ' ) ) {
    printf( "`%s'\n", s.c_str() );
  }
}

Answer 5

Can you use boost?

samm$ cat split.cc
#include <boost/algorithm/string/classification.hpp>
#include <boost/algorithm/string/split.hpp>

#include <boost/foreach.hpp>

#include <iostream>
#include <string>
#include <vector>

int
main()
{
    std::string split_me( "hello world  how are   you" );

    typedef std::vector<std::string> Tokens;
    Tokens tokens;
    boost::split( tokens, split_me, boost::is_any_of(" ") );

    std::cout << tokens.size() << " tokens" << std::endl;
    BOOST_FOREACH( const std::string& i, tokens ) {
        std::cout << "'" << i << "'" << std::endl;
    }
}

sample execution:

samm$ ./a.out
8 tokens
'hello'
'world'
''
'how'
'are'
''
''
'you'
samm$ 

Answer 6

If you are not averse to boost, boost.tokenizer is flexible enough to solve this

#include <string>
#include <iostream>
#include <boost/tokenizer.hpp>

void split_and_show(const std::string s)
{
    boost::char_separator<char> sep(" ", "", boost::keep_empty_tokens);
    boost::tokenizer<boost::char_separator<char> > tok(s, sep);
    for(auto i = tok.begin(); i!=tok.end(); ++i)
            std::cout << '"' << *i << "\"\n";
}
int main()
{
    split_and_show("This is a string");
    split_and_show("This  is a string");

}

test: https://ideone.com/mN2sR