How would I convert this code to C++?
string[] strarr = {\"ram\",\"mohan\",\"sita\"};
foreach(string str in strarr) {
listbox.items.add(str);
}
Something like:
const char* strarr = {"ram","mohan","sita", 0L};
for(int i = 0; strarr[i]; ++i)
{
listbox.items.add(strarr[i]);
}
Also works for standard C. Not sure in C++ how to detect the end of the strarr without having a null element, but the above should work.
After getting used to the var
keyword in C#, I'm starting to use the auto
keyword in C++11. They both determine type by inference and are useful when you just want the compiler to figure out the type for you. Here's the C++11 port of your code:
#include <array>
#include <string>
using namespace std;
array<string, 3> strarr = {"ram", "mohan", "sita"};
for(auto str: strarr) {
listbox.items.add(str);
}
Just for fun (new lambda functions):
static std::list<string> some_list;
vector<string> s;
s.push_back("a");
s.push_back("b");
s.push_back("c");
for_each( s.begin(), s.end(), [=](string str)
{
some_list.push_back(str);
}
);
for_each( some_list.begin(), some_list.end(), [](string ss) { cout << ss; } );
Although doing a simple loop is recommended :-)
The simple form:
std::string data[] = {"ram","mohan","sita"};
std::for_each(data,data+3,std::bind1st(std::mem_fun(&Y::add), &(listbox.items)));
An example in action:
#include <algorithm>
#include <string>
#include <iostream>
#include <functional>
class Y
{
public:
void add(std::string value)
{
std::cout << "Got(" << value << ")\n";
}
};
class X
{
public:
Y items;
};
int main()
{
X listbox;
std::string data[] = {"ram","mohan","sita"};
std::for_each(data,data+3,std::bind1st(std::mem_fun(&Y::add), &(listbox.items)));
}
In C++0x you have
for(string str: strarr) { ... }
But till then use ordinary for loop.
using C++ 14:
#include <string>
#include <vector>
std::vector<std::string> listbox;
...
std::vector<std::string> strarr {"ram","mohan","sita"};
for (const auto &str : strarr)
{
listbox.push_back(str);
}