Convert seconds to days, minutes, and hours in Obj-c

Question

In objective-c, how can I convert an integer (representing seconds) to days, minutes, an hours?

Thanks!

Answer 1

I know this is an old post but I wanted to share anyway. The following code is what I use.

int seconds = (totalSeconds % 60);
int minutes = (totalSeconds % 3600) / 60;
int hours = (totalSeconds % 86400) / 3600;
int days = (totalSeconds % (86400 * 30)) / 86400;

First line - We get the remainder of seconds when dividing by number of seconds in a minutes.

Second line - We get the remainder of seconds after dividing by the number of seconds in an hour. Then we divide that by seconds in a minute.

Third line - We get the remainder of seconds after dividing by the number of seconds in a day. Then we divide that by the number of seconds in a hour.

Fourth line - We get the remainder of second after dividing by the number of seconds in a month. Then we divide that by the number of seconds in a day. We could just use the following for Days...

int days = totalSeconds / 86400;

But if we used the above line and wanted to continue on and get months we would end up with 1 month and 30 days when we wanted to get just 1 month.

Open up a Playground in Xcode and try it out.

Answer 2

You will get days,hours,minutes and seconds from total seconds(self.secondsLeft)

days = self.secondsLeft/86400;
hours = (self.secondsLeft %86400)/3600;
minutes = (self.secondsLeft % 3600) / 60;
seconds = (self.secondsLeft %3600) % 60;

Code ......

  [NSTimer scheduledTimerWithTimeInterval: 1.0 target:self selector:@selector(updateCountdown) userInfo:nil repeats: YES];

-(void) updateCountdown {

    int days,hours,minutes,seconds;
    self.secondsLeft--;

    days = self.secondsLeft/86400;
    hours = (self.secondsLeft %86400)/3600;
    minutes = (self.secondsLeft % 3600) / 60;
    seconds = (self.secondsLeft %3600) % 60;

    NSLog(@"Time Remaining =%@",[NSString stringWithFormat:@"%02d:%02d:%02d:%02d",days, hours, minutes,seconds]);
}

Answer 3

The most preferred way in objective-c might be this one, as recommend by Apple in their doc.

  NSDate *startDate = [NSDate date];
    NSDate *endDate = [NSDate dateWithTimeInterval:(365*24*60*60*3+24*60*60*129) sinceDate:startDate];

    NSCalendar *gregorian = [[NSCalendar alloc]
                             initWithCalendarIdentifier:NSGregorianCalendar];

    NSUInteger unitFlags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit;
    NSDateComponents *components = [gregorian components:unitFlags
                                                fromDate:startDate
                                                  toDate:endDate options:0];
    NSInteger years = [components year];
    NSInteger months = [components month];
    NSInteger days = [components day]; 
    NSLog(@"years = %ld months = %ld days = %ld",years,months,days);

Make sure not to retrieve components not defined with the unitFlags, integer will be "undefined".

Answer 4

Use the built-in function strftime():

static char timestr[80];
char * HHMMSS ( time_t secs )
{
    struct tm ts;
    ts = *localtime(&secs);
    strftime(timestr, sizeof(timestr), "%a %b %d %H:%M:%S %Y %Z", &ts); // "Mon May 1, 2012 hh:mm:ss zzz"
    return timestr;
}

Answer 5

Just a bit modification for both compatible with 32 bit & 64 bit. Using NSIntegerthe system will automatically convert to int or long basing on 32/64 bit.

NSInteger seconds = 10000;
NSInteger remainder = seconds % 3600;
NSInteger hours = seconds / 3600;
NSInteger minutes = remainder / 60;
NSInteger forSeconds = remainder % 60;

By the same way you can convert to days, weeks, months, years