Get mySQL MONTH() to use leading zeros?

Question

How do I specify to mySQL\'s MONTH() function to return \'08\' instead of 8 in this query?

I\'d like the sort to work datewise. Currently getting results for date l

Answer 1

You can use padding like

SELECT
    COUNT(*), 
    CONCAT(YEAR(`datetime_added`), '-', LPAD(MONTH(`datetime_added`), 2, '0')) as date 
FROM `person` 
WHERE (email = '' OR email IS NULL) 
GROUP BY date 
ORDER BY date ASC

Answer 2

Use the following instead:

DATE_FORMAT(`datetime_added`,'%Y-%m')

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Explanation:

DATE_FORMAT() function lets you format the date anyway you like using specifiers described in the table below (taken verbatim from documentation). So a format string '%Y-%m' means: "A full year (4 digits), followed by a dash (-), followed by a two-digit month number".

Note that you can specify the language used for day/month names by setting lc_time_names system variable. Extremely useful. Refer to documentation for more details.

Specifier   Description
%a  Abbreviated weekday name (Sun..Sat)
%b  Abbreviated month name (Jan..Dec)
%c  Month, numeric (0..12)
%D  Day of the month with English suffix (0th, 1st, 2nd, 3rd, …)
%d  Day of the month, numeric (00..31)
%e  Day of the month, numeric (0..31)
%f  Microseconds (000000..999999)
%H  Hour (00..23)
%h  Hour (01..12)
%I  Hour (01..12)
%i  Minutes, numeric (00..59)
%j  Day of year (001..366)
%k  Hour (0..23)
%l  Hour (1..12)
%M  Month name (January..December)
%m  Month, numeric (00..12)
%p  AM or PM
%r  Time, 12-hour (hh:mm:ss followed by AM or PM)
%S  Seconds (00..59)
%s  Seconds (00..59)
%T  Time, 24-hour (hh:mm:ss)
%U  Week (00..53), where Sunday is the first day of the week
%u  Week (00..53), where Monday is the first day of the week
%V  Week (01..53), where Sunday is the first day of the week; used with %X
%v  Week (01..53), where Monday is the first day of the week; used with %x
%W  Weekday name (Sunday..Saturday)
%w  Day of the week (0=Sunday..6=Saturday)
%X  Year for the week where Sunday is the first day of the week, numeric, four digits; used with %V
%x  Year for the week, where Monday is the first day of the week, numeric, four digits; used with %v
%Y  Year, numeric, four digits
%y  Year, numeric (two digits)
%%  A literal “%” character
%x  x, for any “x” not listed above 

Answer 3

DATE_FORMAT(`datetime_added`,'%Y - %m')

Answer 4

MONTH() returns an integer, so of course there's no leading zero. You will need to convert it to a string, left-pad the '0' and take the last 2 characters.