Ubuntu bash script: how to split path by last slash?

Question

I have a file (say called list.txt) that contains relative paths to files, one path per line, i.e. something like this:

foo/bar/file1
foo/bar/ba         


        

Answer 1

Here is one example to find and replace file extensions to xml.

for files in $(ls); do

    filelist=$(echo $files |cut -f 1 -d ".");
    mv $files $filelist.xml;
done

Answer 2

Great solution from this source

p=/foo/bar/file1
path=$( echo ${p%/*} )
file=$( echo ${p##/*/} )

This also works with spaces in the path!

Answer 3

Use basename and dirname, that's all you need.

part1=`dirname "$p"`
part2=`basename "$p"`

Answer 4

A proper 100% bash way and which is safe regarding filenames that have spaces or funny symbols (provided inner_process.sh handles them correctly, but that's another story):

while read -r p; do
    [[ "$p" == */* ]] || p="./$p"
    inner_process.sh "${p%/*}" "${p##*/}"
done < list.txt

and it doesn't fork dirname and basename (in subshells) for each file.

The line [[ "$p" == */* ]] || p="./$p" is here just in case $p doesn't contain any slash, then it prepends ./ to it.

See the Shell Parameter Expansion section in the Bash Reference Manual for more info on the % and ## symbols.