How to create number input field in Flutter?

Question

I\'m unable to find a way to create an input field in Flutter that would open up a numeric keyboard. Is this possible with Flutter material widgets? Some github discussions

Answer 1

You can try this:

TextFormField(
     keyboardType: TextInputType.number,
     decoration: InputDecoration(
              prefixIcon: Text("Enter your number: ")
     ),
     initialValue: "5",
     onSaved: (input) => _value = num.tryParse(input),
),

Answer 2

You can specify the number as keyboardType for the TextField using:

keyboardType: TextInputType.number

Check my main.dart file

import 'package:flutter/material.dart';
import 'package:flutter/services.dart';

void main() => runApp(new MyApp());

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    // TODO: implement build
    return new MaterialApp(
      home: new HomePage(),
      theme: new ThemeData(primarySwatch: Colors.blue),
    );
  }
}

class HomePage extends StatefulWidget {
  @override
  State<StatefulWidget> createState() {
    return new HomePageState();
  }
}

class HomePageState extends State<HomePage> {
  @override
  Widget build(BuildContext context) {
    return new Scaffold(
      backgroundColor: Colors.white,
      body: new Container(
          padding: const EdgeInsets.all(40.0),
          child: new Column(
        mainAxisAlignment: MainAxisAlignment.center,
        children: <Widget>[
          new TextField(
            decoration: new InputDecoration(labelText: "Enter your number"),
            keyboardType: TextInputType.number,
            inputFormatters: <TextInputFormatter>[
    FilteringTextInputFormatter.digitsOnly
], // Only numbers can be entered
          ),
        ],
      )),
    );
  }
}

Answer 3

Set the keyboard and a validator

String numberValidator(String value) {
  if(value == null) {
    return null;
  }
  final n = num.tryParse(value);
  if(n == null) {
    return '"$value" is not a valid number';
  }
  return null;
}

new TextFormField(
    keyboardType: TextInputType.number, 
    validator: numberValidator, 
    textAlign: TextAlign.right
    ...

• https://docs.flutter.io/flutter/material/TextFormField/TextFormField.html
• https://docs.flutter.io/flutter/services/TextInputType-class.html

Answer 4

You can Easily change the Input Type using the keyboardType Parameter and you have a lot of possibilities check the documentation TextInputType so you can use the number or phone value

 new TextField(keyboardType: TextInputType.number)

Answer 5

For those who are looking for making TextField or TextFormField accept only numbers as input, try this code block :

for flutter 1.20 or newer versions

TextFormField(
              controller: _controller,
              keyboardType: TextInputType.number,
              inputFormatters: <TextInputFormatter>[
                FilteringTextInputFormatter.allow(RegExp(r'[0-9]')),
              ],
              decoration: InputDecoration(
                  labelText: "whatever you want",
                  hintText: "whatever you want",
                  icon: Icon(Icons.phone_iphone)))

for earlier versions of 1.20

TextFormField(
    controller: _controller,
    keyboardType: TextInputType.number,
    inputFormatters: <TextInputFormatter>[
        WhitelistingTextInputFormatter.digitsOnly
    ],
    decoration: InputDecoration(
        labelText:"whatever you want", 
        hintText: "whatever you want",
        icon: Icon(Icons.phone_iphone)
    )
)

Answer 6

Here is code for numeric keyboard : keyboardType: TextInputType.phone When you add this code in textfield it will open numeric keyboard.

  final _mobileFocus = new FocusNode();
  final _mobile = TextEditingController();


     TextFormField(
          controller: _mobile,
          focusNode: _mobileFocus,
          maxLength: 10,
          keyboardType: TextInputType.phone,
          decoration: new InputDecoration(
            counterText: "",
            counterStyle: TextStyle(fontSize: 0),
            hintText: "Mobile",
            border: InputBorder.none,
            hintStyle: TextStyle(
              color: Colors.black,
                fontSize: 15.0.
            ),
          ),
          style: new TextStyle(
              color: Colors.black,
              fontSize: 15.0,
           ),
          );