jQuery each loop in table row [duplicate]

Answer 1

Just a recommendation:

I'd recommend using the DOM table implementation, it's very straight forward and easy to use, you really don't need jQuery for this task.

var table = document.getElementById('tblOne');

var rowLength = table.rows.length;

for(var i=0; i<rowLength; i+=1){
  var row = table.rows[i];

  //your code goes here, looping over every row.
  //cells are accessed as easy

  var cellLength = row.cells.length;
  for(var y=0; y<cellLength; y+=1){
    var cell = row.cells[y];

    //do something with every cell here
  }
}

Answer 2

In jQuery just use:

$('#tblOne > tbody  > tr').each(function() {...code...});

Using the children selector (>) you will walk over all the children (and not all descendents), example with three rows:

$('table > tbody  > tr').each(function(index, tr) { 
   console.log(index);
   console.log(tr);
});

Result:

0
<tr>
1 
<tr>
2
<tr>

---

In VanillaJS you can use document.querySelectorAll() and walk over the rows using forEach()

[].forEach.call(document.querySelectorAll('#tblOne > tbody  > tr'), function(index, tr) {
    /* console.log(index); */
    /* console.log(tr); */
});

Answer 3

Use immediate children selector >:

$('#tblOne > tbody  > tr')

Description: Selects all direct child elements specified by "child" of elements specified by "parent".