In Clojure, I want to combine two lists to give a list of pairs,
> (zip \'(1 2 3) \'(4 5 6))
((1 4) (2 5) (3 6))
In Haskell or Ruby t
(map vector '(1 2 3) '(4 5 6))
does what you want:
=> ([1 4] [2 5] [3 6])
Haskell needs a collection of zipWith
(zipWith3
, zipWith4
, ...) functions, because they all need to be of a specific type; in particular, the number of input lists they accept needs to be fixed. (The zip
, zip2
, zip3
, ... family can be regarded as a specialisation of the zipWith
family for the common use case of tupling).
In contrast, Clojure and other Lisps have good support for variable arity functions; map
is one of them and can be used for "tupling" in a manner similar to Haskell's
zipWith (\x y -> (x, y))
The idiomatic way to build a "tuple" in Clojure is to construct a short vector, as displayed above.
(Just for completeness, note that Haskell with some basic extensions does allow variable arity functions; using them requires a good understanding of the language, though, and the vanilla Haskell 98 probably doesn't support them at all, thus fixed arity functions are preferrable for the standard library.)
The built-in way would simply be the function 'interleave':
(interleave [1 2 3 4] [5 6 7 8]) => [1 5 2 6 3 7 4 8]
There is a function called zipmap, that may have the similar effect,
(zipmap (1 2 3)
(4 5 6))
The ouput is as fllows:
{3 6, 2 5, 1 4}
(map vector [1 2 3] [4 5 6])
(partition 2 (interleave '(1 2 3) '(4 5 6)))
=> ((1 4) (2 5) (3 6))
or more generally
(defn zip [& colls]
(partition (count colls) (apply interleave colls)))
(zip '( 1 2 3) '(4 5 6)) ;=> ((1 4) (2 5) (3 6))
(zip '( 1 2 3) '(4 5 6) '(2 4 8)) ;=> ((1 4 2) (2 5 4) (3 6 8))
#(apply map list %) transposes a matrix just like the Python zip* function. As a macro definition:
user=> (defmacro py-zip [lst] `(apply map list ~lst))
#'user/py-zip
user=> (py-zip '((1 2 3 4) (9 9 9 9) (5 6 7 8)))
((1 9 5) (2 9 6) (3 9 7) (4 9 8))
user=> (py-zip '((1 9 5) (2 9 6) (3 9 7) (4 9 8)))
((1 2 3 4) (9 9 9 9) (5 6 7 8))