Using Gulp to build requireJS project - gulp-requirejs

Question

I am trying to use gulp-requirejs to build a demo project. I expect result to be a single file with all js dependencies and template included. Here is my gulpfile.js

Answer 1

UPDATE

My previous answer always reported taskReady even if requirejs reported an error. I reconsidered this approach and added error logging. Also I try to fail the build completely as described here gulp-jshint: How to fail the build? because a silent fail really eats your time. See updated code below.

Drew's comment about blacklist was very helpfull and gulp folks suggest using requirejs directly. So I post my direct requirejs solution:

var DIST = './dist';
var requirejs = require('requirejs');
var requirejsConfig = require('./requireConfig.js').RJSConfig;

gulp.task('requirejs', function (taskReady) {
    requirejsConfig.name = 'index';
    requirejsConfig.out = DIST + 'app.js';
    requirejsConfig.optimize = 'uglify';
    requirejs.optimize(requirejsConfig, function () {
        taskReady();
    }, function (error) {
        console.error('requirejs task failed', JSON.stringify(error))
        process.exit(1);
    });
});

The file at ./dist/app.js is built and uglified. And this way gulp will know when require has finished building. So the task can be used as a dependency.