Is \d not supported by grep's basic expressions?

Question

This does not generate any output. How come?

$ echo \'this 1 2 3\' | grep \'\\d\\+\'

But these do:

$ echo \'this 1 2 3\' |          


        

Answer 1

Try this $ echo 'this 1 2 3' | grep '[0-9]\+'

Answer 2

grep's default mode is (iirc) POSIX regex, and \d is pcre. You can either pass -P to gnu grep, for perl-like regexps, or use [[:digit:]] instead of \d.

daenyth@Bragi ~ $ echo 1 | grep -P '\d'
1
daenyth@Bragi ~ $ echo 1 | grep '[[:digit:]]'
1