Postgresql Select rows where column = array

Question

This is a summary of what I am trying to do:

$array[0] = 1;
$array[1] = 2;

$sql = \"SELECT * FROM table WHERE some_id = $array\"

Obviously

Answer 1

SELECT  *
FROM    table
WHERE   some_id = ANY(ARRAY[1, 2])

or ANSI-compatible:

SELECT  *
FROM    table
WHERE   some_id IN (1, 2)

The ANY syntax is preferred because the array as a whole can be passed in a bound variable:

SELECT  *
FROM    table
WHERE   some_id = ANY(?::INT[])

You would need to pass a string representation of the array: {1,2}

Answer 2

For dynamic SQL use:

'IN(' ||array_to_string(some_array, ',')||')'

Example

DO LANGUAGE PLPGSQL $$

DECLARE
    some_array bigint[];
    sql_statement text;

BEGIN

    SELECT array[1, 2] INTO some_array;
    RAISE NOTICE '%', some_array;

    sql_statement := 'SELECT * FROM my_table WHERE my_column IN(' ||array_to_string(some_array, ',')||')';
    RAISE NOTICE '%', sql_statement;

END;

$$;

Result: NOTICE: {1,2} NOTICE: SELECT * FROM my_table WHERE my_column IN(1,2)

Answer 3

   $array[0] = 1;
   $array[2] = 2;
   $arrayTxt = implode( ',', $array);
   $sql = "SELECT * FROM table WHERE some_id in ($arrayTxt)"

Answer 4

In my case, I needed to work with a column that has the data, so using IN() didn't work. Thanks to @Quassnoi for his examples. Here is my solution:

SELECT column(s) FROM table WHERE expr|column = ANY(STRING_TO_ARRAY(column,',')::INT[])

I spent almost 6 hours before I stumble on the post.