How to get a list of all users with a specific permission group in Django

Question

I want to get a list of all Django auth user with a specific permission group, something like this:

user_dict = {
    \'queryset\': User.objects.filter(permi         


        

Answer 1

I think for group permissions, permissions are stored against groups, and then users have groups linked to them. So you can just resolve the user - groups relation.

e.g.

518$ python manage.py shell

(InteractiveConsole)
>>> from django.contrib.auth.models import User, Group
>>> User.objects.filter(groups__name='monkeys')
[<User: cms>, <User: dewey>]

Answer 2

Based on @Glader's answer, this function wraps it up in a single query, and has been modified to algo get the superusers (as by definition, they have all perms):

from django.contrib.auth.models import User
from django.db.models import Q

def users_with_perm(perm_name):
    return User.objects.filter(
        Q(is_superuser=True) |
        Q(user_permissions__codename=perm_name) |
        Q(groups__permissions__codename=perm_name)).distinct()

# Example:
queryset = users_with_perm('blogger')

Answer 3

If you want to get list of users by permission, look at this variant:

from django.contrib.auth.models import User, Permission
from django.db.models import Q

perm = Permission.objects.get(codename='blogger')  
users = User.objects.filter(Q(groups__permissions=perm) | Q(user_permissions=perm)).distinct()

Answer 4

This would be the easiest

from django.contrib.auth import models

group = models.Group.objects.get(name='blogger')
users = group.user_set.all()

Answer 5

Groups are many-to-many with Users (you see, nothing unusual, just Django models...), so the answer by cms is right. Plus this works both ways: having a group, you can list all users in it by inspecting user_set attribute.

Answer 6

Based on @Augusto's answer, I did the following with a model manager and using the authtools library. This is in querysets.py:

from django.db.models import Q
from authtools.models import UserManager as AuthUserManager

class UserManager(AuthUserManager):
    def get_users_with_perm(self, perm_name):
        return self.filter(
                Q(user_permissions__codename=perm_name) |
                Q(groups__permissions__codename=perm_name)).distinct()

And then in models.py:

from django.db import models
from authtools.models import AbstractEmailUser
from .querysets import UserManager


class User(AbstractEmailUser):
   objects = UserManager()