What does %s and %d mean in printf in the C language? [closed]

Answer 1

% notation is called a format specifier. For example, %d tells printf() to print an integer. %s to print a string (char *) etc. You should really look it up here: http://google.com/search?q=printf+format+specifiers

No, commas are not used for string concatenation. Commas are for separating arguments passed to a function.

Answer 2

%s%d%s%d\n is a format string. It is used to specify how the information is formatted on an output. here the format string is supposed to print string followed by a digit followed by a string and then again a digit. The last symbol \n represents carriage return which marks the end of a line. In C, strings cannot be concatenated by + or , although you can combine different outputs on a single line by using the appropriate format strings (the use of format strings is to format output info.).

Answer 3

The first argument denotes placeholders for the variables / parameters that follow.
For example, %s indicates that you're expecting a String to be your first print parameter.

Java also has a printf, which is very similar.

Answer 4

The first argument to printf is a string of identifiers.

%s refers to a string %d refers to an integer %c refers to a character. Therefore: %s%d%s%c\n prints the string "The first character in sting ", %d prints i, %s prints " is ", and %c prints str[0].

Answer 5

%(letter) denotes the format type of the replacement text. %s specifies a string, %d an integer, and %c a char.

Answer 6

%d is print as an int %s is print as a string %f is print as floating point

It should be noted that it is incorrect to say that this is different from Java. Printf stands for print format, if you do a formatted print in Java, this is exactly the same usage. This may allow you to solve interesting and new problems in both C and Java!