How can I validate a string using Regular Expressions to only allow alphanumeric characters in it?
(I don\'t want to allow for any spaces either).
Same answer as here.
If you want a non-regex ASCII A-z 0-9
check, you cannot use char.IsLetterOrDigit()
as that includes other Unicode characters.
What you can do is check the character code ranges.
The following is a bit more verbose, but it's for ease of understanding rather than for code golf.
public static bool IsAsciiAlphaNumeric(this string str)
{
if (string.IsNullOrEmpty(str))
{
return false;
}
for (int i = 0; i < str.Length; i++)
{
if (str[i] < 48) // Numeric are 48 -> 57
{
return false;
}
if (str[i] > 57 && str[i] < 65) // Capitals are 65 -> 90
{
return false;
}
if (str[i] > 90 && str[i] < 97) // Lowers are 97 -> 122
{
return false;
}
if (str[i] > 122)
{
return false;
}
}
return true;
}
In order to check if the string is both a combination of letters and digits, you can re-write @jgauffin answer as follows using .NET 4.0 and LINQ:
if(!string.IsNullOrWhiteSpace(yourText) &&
yourText.Any(char.IsLetter) && yourText.Any(char.IsDigit))
{
// do something here
}
I needed to check for A-Z, a-z, 0-9; without a regex (even though the OP asks for regex).
Blending various answers and comments here, and discussion from https://stackoverflow.com/a/9975693/292060, this tests for letter or digit, avoiding other language letters, and avoiding other numbers such as fraction characters.
if (!String.IsNullOrEmpty(testString)
&& testString.All(c => Char.IsLetterOrDigit(c) && (c < 128)))
{
// Alphanumeric.
}
^\w+$
will allow a-zA-Z0-9_
Use ^[a-zA-Z0-9]+$
to disallow underscore.
Note that both of these require the string not to be empty. Using *
instead of +
allows empty strings.