Adding a simple UIAlertView

Question

What is some starter code I could use to make a simple UIAlertView with one \"OK\" button on it?

Answer 1

Other answers already provide information for iOS 7 and older, however UIAlertView is deprecated in iOS 8.

In iOS 8+ you should use UIAlertController. It is a replacement for both UIAlertView and UIActionSheet. Documentation: UIAlertController Class Reference. And a nice article on NSHipster.

To create a simple Alert View you can do the following:

UIAlertController *alertController = [UIAlertController alertControllerWithTitle:@"Title"
                                                                         message:@"Message"
                                                                  preferredStyle:UIAlertControllerStyleAlert];
//We add buttons to the alert controller by creating UIAlertActions:
UIAlertAction *actionOk = [UIAlertAction actionWithTitle:@"Ok"
                                                   style:UIAlertActionStyleDefault
                                                 handler:nil]; //You can use a block here to handle a press on this button
[alertController addAction:actionOk];
[self presentViewController:alertController animated:YES completion:nil];

Swift 3 / 4 / 5:

let alertController = UIAlertController(title: "Title", message: "Message", preferredStyle: .alert)
//We add buttons to the alert controller by creating UIAlertActions:
let actionOk = UIAlertAction(title: "OK",
    style: .default,
    handler: nil) //You can use a block here to handle a press on this button

alertController.addAction(actionOk)

self.present(alertController, animated: true, completion: nil)

Note, that, since it was added in iOS 8, this code won't work on iOS 7 and older. So, sadly, for now we have to use version checks like so:

NSString *alertTitle = @"Title";
NSString *alertMessage = @"Message";
NSString *alertOkButtonText = @"Ok";

if (@available(iOS 8, *)) {
    UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:alertTitle
                                                        message:alertMessage
                                                       delegate:nil
                                              cancelButtonTitle:nil
                                              otherButtonTitles:alertOkButtonText, nil];
    [alertView show];
}
else {
    UIAlertController *alertController = [UIAlertController alertControllerWithTitle:alertTitle
                                                                             message:alertMessage
                                                                      preferredStyle:UIAlertControllerStyleAlert];
    //We add buttons to the alert controller by creating UIAlertActions:
    UIAlertAction *actionOk = [UIAlertAction actionWithTitle:alertOkButtonText
                                                       style:UIAlertActionStyleDefault
                                                     handler:nil]; //You can use a block here to handle a press on this button
    [alertController addAction:actionOk];
    [self presentViewController:alertController animated:YES completion:nil];
}

Swift 3 / 4 / 5:

let alertTitle = "Title"
let alertMessage = "Message"
let alertOkButtonText = "Ok"

if #available(iOS 8, *) {
    let alertController = UIAlertController(title: alertTitle, message: alertMessage, preferredStyle: .alert)
    //We add buttons to the alert controller by creating UIAlertActions:
    let actionOk = UIAlertAction(title: alertOkButtonText,
        style: .default,
        handler: nil) //You can use a block here to handle a press on this button

    alertController.addAction(actionOk)
    self.present(alertController, animated: true, completion: nil)
}
else {
    let alertView = UIAlertView(title: alertTitle, message: alertMessage, delegate: nil, cancelButtonTitle: nil, otherButtonTitles: alertOkButtonText)
    alertView.show()
}

UPD: updated for Swift 5. Replaced outdated class presence check with availability check in Obj-C.

Answer 2

Simple alert with array data:

NSString *name = [[YourArray objectAtIndex:indexPath.row ]valueForKey:@"Name"];

NSString *msg = [[YourArray objectAtIndex:indexPath.row ]valueForKey:@"message"];

UIAlertView *alert = [[UIAlertView alloc] initWithTitle:name
                                                message:msg
                                               delegate:self
                                      cancelButtonTitle:@"OK"
                                      otherButtonTitles:nil];
[alert show];

Answer 3

Here is a complete method that only has one button, an 'ok', to close the UIAlert:

- (void) myAlert: (NSString*)errorMessage
{
    UIAlertView *myAlert = [[UIAlertView alloc]
                          initWithTitle:errorMessage
                          message:@""
                          delegate:self
                          cancelButtonTitle:nil
                          otherButtonTitles:@"ok", nil];
    myAlert.cancelButtonIndex = -1;
    [myAlert setTag:1000];
    [myAlert show];
}

Answer 4

UIAlertView is deprecated on iOS 8. Therefore, to create an alert on iOS 8 and above, it is recommended to use UIAlertController:

UIAlertController *alert = [UIAlertController alertControllerWithTitle:@"Title" message:@"Alert Message" preferredStyle:UIAlertControllerStyleAlert];
UIAlertAction *defaultAction = [UIAlertAction actionWithTitle:@"Ok" style:UIAlertActionStyleDefault handler:^(UIAlertAction *action){

    // Enter code here
}];
[alert addAction:defaultAction];

// Present action where needed
[self presentViewController:alert animated:YES completion:nil];

This is how I have implemented it.

Answer 5

UIAlertView *alert = [[UIAlertView alloc]
 initWithTitle:@"Title" 
 message:@"Message" 
 delegate:nil //or self
 cancelButtonTitle:@"OK"
 otherButtonTitles:nil];

 [alert show];
 [alert autorelease];

Answer 6

As a supplementary to the two previous answers (of user "sudo rm -rf" and "Evan Mulawski"), if you don't want to do anything when your alert view is clicked, you can just allocate, show and release it. You don't have to declare the delegate protocol.