Simplest way to write this AJAX call

Question

I need to send an ajax request to a webserver \"http://examples.com/ajax\" the response will be the html of a

and it will be inserted to an existing

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Answer 1

var req = new XMLHttpRequest();

req.onreadystatechange = function() {
  //Is request finished? Does the requested page exist?
  if(req.readyState==4 && req.status==200) {   
    //Your HTML arrives here
    alert(req.responseText);  
  }
}

req.open("GET","http://examples.com/ajax.php",true)  //true indicates ASYNCHRONOUS
req.send(null);

This solution uses get, so you've got to add variables using ? and & to your URL (e.g. http://examples.com/ajax.php?foo=bar&blah=blee.

If you want to do it using post, run a few with get and then this article is useful.