I have a table that looks like
Test Reader Result
1 John 1.6
1 Jack 5.2
2 Ursula 2.5
3 Albert 3.0
2 Jack 5
See my comment above. I tried to convert for your table (T1):
WITH TX AS (SELECT TEST, READER, RESULT, ROW_NUMBER() OVER (PARTITION BY TEST ORDER BY READER) AS RN
FROM T1
)
SELECT T0.TEST
, TT1.READER AS READER_1
, TT1.RESULT AS RESULT_1
, TT2.READER AS READER_2
, TT2.RESULT AS RESULT_2
, TT3.READER AS READER_3
, TT3.RESULT AS RESULT_3
FROM (SELECT DISTINCT TEST FROM T1) AS T0
LEFT JOIN TX TT1 ON T0.TEST = TT1.TEST AND TT1.RN=1
LEFT JOIN TX TT2 ON T0.TEST = TT2.TEST AND TT2.RN=2
LEFT JOIN TX TT3 ON T0.TEST = TT3.TEST AND TT3.RN=3;
A solution that does not require multiple self-joins:
You can PIVOT
on the result of the ROW_NUMBER()
analytic function to get your desired output:
SELECT *
FROM (
SELECT t.*,
ROW_NUMBER() OVER ( PARTITION BY test ORDER BY ROWNUM ) AS rn
FROM your_table t
)
PIVOT ( MAX( Reader ) AS reader, MAX( result ) AS result FOR rn IN ( 1, 2, 3 ) );
Output:
TEST 1_READER 1_RESULT 2_READER 2_RESULT 3_READER 3_RESULT
---- -------- -------- -------- -------- -------- --------
1 John 1.6 Jack 5.2
2 Ursula 2.5 Jack 5.1
3 Albert 3.0
Or, just using aggregation functions:
SELECT test,
MAX( CASE rn WHEN 1 THEN reader END ) AS reader_1,
MAX( CASE rn WHEN 1 THEN result END ) AS result_1,
MAX( CASE rn WHEN 2 THEN reader END ) AS reader_2,
MAX( CASE rn WHEN 2 THEN result END ) AS result_2,
MAX( CASE rn WHEN 3 THEN reader END ) AS reader_3,
MAX( CASE rn WHEN 3 THEN result END ) AS result_3
FROM (
SELECT t.*,
ROW_NUMBER() OVER ( PARTITION BY test ORDER BY ROWNUM ) AS rn
FROM your_table t
)
GROUP BY test;